Calculating lens focal point and size for head mounted display I am trying to make a single-eye head mounted display.
It will be a prototype for displaying information while the person is doing other work. The important part is that the virtual image of the screen is around 1 meter away from the wearer so he will not have to adjust his focus much while working with his hands.
However I cant figure out the parameters of my lens. I have made a graphic to explain the situation:

I want to get my fixed screen size to cover all of the FOV, F,B and possibly C(adjustable) can be derived.


*

*Is it possible to make a function out of this using the lens formula? 

*My field does not have to be perfectly flat, do i still have to worry about weird optical effect just using a biconvex lens?


Any tips on how to get my values are greatly appreciated.
 A: It is indeed an interesting project.
I have a better idea. If you have the convex lens of focal length $C$, then the image will be at $\infty$ and your eye can see it easily. In this case the magnification will be $\frac{f_{eye}}{f_L}$. Usually the eye focal length is taken as 55 mm and the lens you will need is ~10 mm then the magnification of 5 will be there and one can see the small images clearly. You may also want to make them as reading glasses (top part with 0 power and bottom part with the high power convex lens).
Small changes in the focusing can be done by adjusting the position of the instruction paper relative to the lens using a screw or something. 
I hope this will help
regards,
A: I'm not sure where your actual, physical screen is, but let's assume that it is 1 cm to the right of the lens.  That means you have a negative image distance.
The simple equation for this is
1/f=1/p+1/q 
f=focal length 
p=object distance 
q=image distance 
Then you would have 
p=-1 cm 
q=100 cm 
f=-1.01 cm 
Notice the focal length is negative.  This is not a convex lens, it's concave.
Finding optics like this is going to be tricky, I think.  Also I suspect you'll have to look into aspherical lenses, which will be even trickier.
