This maximum free molecule size can easily be found from Ideal gas law.
$22.414 ~{\rm dm^3/mol}$, at $0 ~^\circ{\rm C}$ and 1 atmosphere.
This means $2.68678\times 10^{25}~{\rm mol/m^3}$ which means that a 1 m row of molecules in these conditions is $\sqrt[3]{2.68678\times 10^{25}}= 299509596.1 \textrm{ molecule/m}$
This alouds to calculate the diameter of a single molecule; $$ d=\frac{1\textrm{ molecule}}{299509596.1 \textrm{ molecule/m}}=3.3 \times 10^{-9} ~{\rm m}$$
When this diameter of a sphere, is used to calculate the area momentum of inertia, which is just a geometrical property. The equation for circular shape in $z$-direction is
$$I_z=\frac{\pi}{2}r^4$$
The meaning of "$z$-direction" can be understood as perpendicular to circular-plane;
Calculating this gives $$I_z=\frac{\pi}{2}r^4=\frac{\pi}{2}\frac{d^4}{2^4}==\frac{\pi\cdot (3.3 \times 10^{-9})^4}{32}=1.164 \times 10^{-35}\textrm{ m}^4$$
And as this area momentum of inertia is used to calculate Deflections, which have a pure exponential shape. (The own mass of structure is neglected, with own mass the form is Catenary.) The inverse of such an exponential shape is natural logarithm. So multiplying this result with $e^4$ gives;
$$h=e^4\frac{\pi}{2}r^4=6.356\times 10^{-34}\textrm{ m}^4$$
Question; Can Planck's constant be derived from the maximum free Molecule size? Means; Is this logic valid? (Compared to ie. Numerology)