I am calculating surface gravity of Kerr Black Hole following 'A Relativist's toolkit' which uses the definition

$$ \left(-\xi^\beta \xi_\beta\right);_\alpha=2\kappa \xi_\alpha$$

where $\kappa$ is the surface gravity. However in the calculation it is used that on the horizon $$\xi_\alpha=\left(1-a\Omega_H\sin^2\theta\right)\partial_\alpha r$$

Can anyone point out how to get this expression for $\xi_\alpha$?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.