# What would this high resistance Voltmeter read?

What would this high resistance Voltmeter read and why? I have only just started A level physics so try to give answers relative to my level of understanding please!

The battery has a negligible internal resistance to be clear.

Let's consider the circuit like a ideal generator of voltage $V_g$ connected to the two series of resistor. When you connect a generator to a series of resistors it behaves like a voltage divider and so the voltage across every resistor is proportional to its resistance. Hence, across the first resistor there will be a voltage of:
$$V_1 = V_g \frac{R_1}{R_1+R_2+R_3}$$
Similarly, across the fourth and fifth resistor there will be a voltage of: $$V_4 = V_g \frac{R_4}{R_4+R_5+R_6}$$ $$V_5 = V_g \frac{R_5}{R_4+R_5+R_6}$$
$$\Delta V_v = (V_4+V_5)-V_1 = V_g \left( \frac{R_4}{R_4+R_5+R_6} +\frac{R_5}{R_4+R_5+R_6}- \frac{R_1}{R_1+R_2+R_3}\right)$$