# A field for the weak nuclear force

This is a thought experiment, and I seek to learn that this is a silly question.

Assume electrons were placed in a plane, and in a parallel plane you were able to confine neutrinos. Given that they have opposite quantum numbers for the third component of weak isospin, would there be a field of the weak force between the two planes?

Obviously the force is mediated by W and Z bosons, which have a very short range. If the two planes are placed within that range, ignoring other effects, what would happen?

• Yes, it is a silly question, but it has been improved to a more meaningful one, alas!, with a negative answer... 89202. – Cosmas Zachos Sep 29 '16 at 22:37

You can't meaningfully take the classical limit of the weak force, because at the scales where you could neglect the quantum interactions, the classical potential of the weak force is suppressed so strongly by the masses of the W- and Z- bosons that it is practically non-existent. This is because forces mediated by massive particles don't follow a pure inverse-square law in their classical limit, but have an additional factor $\exp(-\mu r)$ where $\mu$ is the mass of the mediator.
However, if you just formally take the classical limit and don't care for how physically meaningful it is, then the answer is that the "weak field" you would get would obey a distance law $\propto \frac{\exp(-\mu r)}{r^2}$ instead of the electromagnetic $\propto\frac{1}{r^2}$.