# Why is $0K$ impossible to reach if the heat capacity goes to $0$ as $T$ approaches $0 K$?

I'm confused about the third law of Thermodynamics.

The entropy of a perfect crystal at absolute zero is exactly equal to zero.

A consequence of third law is that

The heat capacity must go to zero at absolute zero

$$\displaystyle \lim _{T\rightarrow 0}C(T,X)=0 \tag{1}$$

The law is also known in this way

In 1912 Nernst stated the law thus: "It is impossible for any procedure to lead to the isotherm $T = 0$ in a finite number of steps."

I do not understand how $(1)$ agrees with the Nernst first statement.

We have $$Q=C \Delta T \implies \Delta T=Q/ C$$

So $C \to 0$ means that a small amount of heat exchanged causes a very large variation of temperature.

So why "it becomes difficult to lower a body's temperatue near $0K$"? Shouldn't it be easier instead ($C \to 0 \implies \Delta T \to \infty$)?

• Nernst statement suggest that it's impossible to actually reach the absolute zero Sep 14, 2016 at 22:57
• Your argument about $\Delta T = \Delta Q/C$ becoming large when $C$ is small suffers from a zero-over-zero problem, since both the heat content and the heat capacity depend on the temperature; it's necessary to tread carefully.
– rob
Sep 14, 2016 at 23:48
• As you pointed out near $0K$ the heat capacity is very small, therefore the slightest heat absorption will lead to a relatively large increase of the body temperature, that is all. Sep 15, 2016 at 1:42

Look at Clausius's statement of the second law of thermodynamics. The short version is that heat only ever flows from high temperature areas to low temperature ones. So, in order bring a body's temperature to $0\operatorname{K}$ by the transfer of heat energy you need to have a $0\operatorname{K}$ heat bath to dump the heat into. Note that a heat bath needs to be able to absorb heat without changing temperature, so the existence of a $0\operatorname{K}$ heat bath would violate the claim in the question that $C\rightarrow 0$ for all bodies as $T\rightarrow 0 \operatorname{K}$.
There are other ways to reach $0\operatorname{K}$ that are equally nonphysical. Adiabatically expanding an ideal gas to infinite volume, for example, will get you to the $0\operatorname{K}$ isotherm. You just need to have an infinite volume to expand into, and an infinite amount of time to do it quasi-statically so you can extract the heat as work.