It's a neutron star, so if electrons fall in, AFAIK , there is no electrostatic repulsive force. Allowing gravity to pull them in one at a time will probably mean that the electrons will get caught up in the magnetic field of the neutron star.
Although Wikipedia says there is no overall net charge, I do wonder how that applies to the outer crust, composed of ions and electrons?
From Neutron Star Wikipedia
Neutron stars are very hot and typically have a surface temperature around $6 ×10^5 K$. They are so dense that a normal-sized matchbox containing neutron-star material would have a mass of approximately 13 million tonnes, or a 2.5 million $m^3$ chunk of the Earth. The density of the star is comparable to that of the nucleus of an atom. They have strong magnetic fields, between $10^8$ and $10^{15}$ times that of Earth's. The gravitational field at the neutron star's surface is about $2 ×10^{11}$ times that of the Earth's.
Image Source: By Robert Schulze - Own work, CC BY-SA 3.0
Neutron stars have strong magnetic fields. The magnetic field strength on the surface of neutron stars have been estimated at least to have the range of $10^8$ to $10^{15}$ gauss ($10^4$ to $10^{11}$ tesla). In comparison, the magnitude at Earth's surface ranges from 25 to 65 microteslas (0.25 to 0.65 gauss), making the field at least $10^8$ times as strong as that of Earth. Variations in magnetic field strengths are most likely the main factor that allows different types of neutron stars to be distinguished by their spectra, and explains the periodicity of pulsars. The neutron stars known as magnetars have the strongest magnetic fields, in the range of $10^8$ to $10^{11}$ tesla, and have become the widely accepted hypothesis for neutron star types soft gamma repeaters (SGRs) and anomalous X-ray pulsars (AXPs).