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What determines the intensity of sound? The frequency determines if it is C or #G but what does determine the loudness (aka intensity)?

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    $\begingroup$ Did you at-least google? $\endgroup$
    – user36790
    Commented Sep 10, 2016 at 16:46
  • $\begingroup$ @MAFIA36790 yes I did $\endgroup$
    – technikfe
    Commented Sep 10, 2016 at 17:19
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    $\begingroup$ My point is if you did, then show your efforts; however, I'm seeing you got the answer. $\endgroup$
    – user36790
    Commented Sep 10, 2016 at 17:22
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    $\begingroup$ Oh, yes; the question will come in the front page when one googles about the same. $\endgroup$
    – user36790
    Commented Sep 10, 2016 at 17:49
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    $\begingroup$ I'm voting to close this question as off-topic because it shows insufficient prior research. $\endgroup$ Commented Sep 10, 2016 at 18:46

1 Answer 1

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The intensity is a measure of the sound pressure in the wave. The excursion from ambient pressure is greater for loud sounds.

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  • $\begingroup$ "excursion from ambient pressure " what does the excursion mean? $\endgroup$
    – technikfe
    Commented Sep 10, 2016 at 16:17
  • $\begingroup$ Sound travels as pockets of high and low pressure. How closely packed they are is equivalent to the frequency and how high/low the pressure is in those pockets is the equivalent to the amplitude. $\endgroup$
    – Ulthran
    Commented Sep 10, 2016 at 16:28
  • $\begingroup$ thnx I think I got it now $\endgroup$
    – technikfe
    Commented Sep 10, 2016 at 16:40

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