Imagine a 1.5V battery with both terminals connected securely via a paperclip.
According to KVL, the sum of voltage drops in the circuit (total energy dissipated across circuit elements) must equal the energy afforded by the supply voltage (take for instance the 1.5V AA battery)
How does one interpret KVL in this case? I cannot simply add the voltage drops across the circuit elements, because there are none. I also know that 1.5 volts must get dropped over the circuit, unless KVL doesn't apply.
Closest thing I could find to being the answer was this: Applying Kirchoff voltage law to a short circuit, however it wasn't satisfying.
My guess is that the wire itself must drop all 1.5V and does so through heating, but who knows I could be wrong. Perhaps in this setup the battery is a "short circuit" and KVL doesn't apply?