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In physics, whenever Fourier analysis is utilised to analyse a problem the term "Fourier mode" is often used, e.g. "a given function can be represented in terms of its Fourier modes". My question is, what exactly is meant by the term "Fourier mode"?

Is it in reference to a given wave oscillating at a fixed frequency? And then a given function is built up from an (infinite) superposition of these waves, each oscillating at a fixed frequency (ranging over a continuous frequency spectrum)?!

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closed as unclear what you're asking by DanielSank, user108787, user36790, Wolpertinger, heather Aug 28 '16 at 12:45

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ This has been asked before. Could you explain in what way the question and answers linked there do not address what you want to know? Also, the second paragraph of the question here is one very long and confusing sentence. You might want to edit it to be more readable. $\endgroup$ – DanielSank Aug 27 '16 at 22:12
  • $\begingroup$ @DanielSank I have updated the question to hopefully make it more comprehensible. I have read the answers in your link, but I'm still unsure of their relation and meaning in Fourier analysis?! $\endgroup$ – user35305 Aug 27 '16 at 22:42
  • $\begingroup$ You say that in the context of Fourier analysis in physics term "frequency mode" is used. I can try to guess when the author means but an example would make it more obvious. I'll write an answer meanwhile and can revise based on your updates. $\endgroup$ – DanielSank Aug 27 '16 at 22:47
  • $\begingroup$ "In particular, what is the relation to the Fourier modes of a given function?" I don't know what that is meant to ask. "Is it in reference to a given time-independent wave oscillating at a fixed frequency?" That's a contradiction in terms. A thing that is time-independent is not oscillating. $\endgroup$ – DanielSank Aug 27 '16 at 22:53
  • $\begingroup$ @DanielSank Good point. I didn't think the wording through correctly there, I meant oscillating at a time independent frequency. I have further updated the question. $\endgroup$ – user35305 Aug 27 '16 at 23:16
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A mode in physics is, generally speaking, the spatial part of a waveform. A Fourier mode, more specifically, is a wave that oscillates sinusoidally in space. Thus, when we write the Fourier transform of a wave function $f(\mathbf r,t)$ as $$ f(\mathbf r,t) = \int\tilde f(\mathbf k,t)e^{i\mathbf k\cdot \mathbf r} \: \mathrm d\mathbf k, $$ the quote you give,

a given function can be represented terms of its Fourier modes,

means exactly that: we have a bunch of Fourier modes, which are the functions $ f(\mathbf k,t)e^{i\mathbf k\cdot \mathbf r}$, with $\mathbf k$ a static parameter, and then we add them all up (via integration over this parameter) to give us back our $f(\mathbf r,t)$.

The term 'mode' isn't used by itself very much, but it does appear with other qualifiers such as the normal modes of a system, which specifically requires a regular sinusoidal oscillation at each and every point of the system. Similarly to Fourier modes, these normal modes can then be used to represent any arbitrary wave as a sum of normal modes.

It's also important to note that 'mode' in general can apply to both continuous and discrete systems, as does 'normal mode'. You can in principle define Fourier modes for an infinite or cyclical chain of discrete coupled masses, characterized by a sinusoidal dependence on the (discrete) spatial index, but this is rarely used. In all of these cases, though, what sets the Fourier modes apart from other modes of oscillation is the sinusoidal spatial dependence.

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  • $\begingroup$ You've got the Fourier transform over spatial modes, but OP is asking about frequency. To link these, we need a wave equation. $\endgroup$ – DanielSank Aug 28 '16 at 0:40
  • $\begingroup$ @Daniel I've yet to see a paper using the term Fourier mode for a temporal oscillation, or indeed other than in the sense I described. If there are other usages I'd be interested, but to be honest the OP is much too muddled to draw distinctions that fine. $\endgroup$ – Emilio Pisanty Aug 28 '16 at 0:47
  • $\begingroup$ I'm not really sure what you mean. A "mode" almost always has spatial and a temporal aspects and a wave equation usually links them. Also, note that I can expand a function in a Fourier series (or transform) regardless of whether it's a function of $x$ or $t$. $\endgroup$ – DanielSank Aug 28 '16 at 1:25
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    $\begingroup$ @EmilioPisanty Ah ok, so at a given instant in time each term $f(\mathbf{k},t)e^{i\mathbf{k}\cdot\mathbf{r}}$ is a waveform oscillating sinusoidally at some fixed spatial frequency $\mathbf{k}$ - a Fourier mode of the function $f(\mathbf{r},t)$ at a given instant in time, t. Each Fourier mode then represents a constituent of the function $f(\mathbf{r},t)$, in the sense that one can synthesise the function in terms of an infinite set of sinusoidal waveforms by integrating over the continuous range of spatial frequencies?! ... $\endgroup$ – user35305 Aug 28 '16 at 9:12
  • $\begingroup$ @EmilioPisanty ... Is they idea then that $f(\mathbf{r},t)$ satisfies some sort of wave equation and consequently the Fourier modes satisfy a corresponding wave equation, which dictates how they must evolve in time such that, at each instant $t$, the function $f(\mathbf{r},t)$ can be represented in terms of these Fourier modes as $f(\mathbf{r},t)=\int\tilde{f}(\mathbf{k},t)e^{i\mathbf{k}\cdot\mathbf{r}}d\mathbf{k}$? $\endgroup$ – user35305 Aug 28 '16 at 9:20

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