How Hawking Radiation can have any meaningful impact on the black hole's life since time is almost stopped right outside the Even Horizon? Every object experiences time more and more slowly as they approach the event horizon until stops right at it, according to observers outside the event horizon. As far as I know quantum fluxuations which happen in that region are the direct reason why black holes evaporate.
How is it possible for the event horizon to not exist anymore since the insane time dilation there makes it so it doesn't experience time? Consequently any quantum flaxuations there would freeze or happen at incredible slow motion far too slow to have any effect on the black hole's mass at all. No particle would neither fall nor travel very far from the event horizon according to our clocks. But the evaporation of the black hole does happen in our clocks.
 A: There are two aspects to be addressed here. 
Firstly it is not true that Hawking radiation is exactly always produced at the Event horizon. Usually  for a field theory, we have vacuum fluctuations where there is creation and annihilation of a particle antiparticle pair. Now since the black hole has an event horizon, one particle can fall into inside the event horizon and the other escapes from the horizon, thereby reducing the total energy of the system in question. The thing is, these processes usually happen near the horizon, but not always. 
Secondly, since the radius of the horizon keeps shrinking continuously due to Hawking radiation, therefore if a particle was very highly red-shifted initially, if won't be so sometime later. Given a black hole of mass M, you can calculate that it radiates its mass away in $t \approx M^3$, since the emitted Hawking radiation is blackbody radiation
The textbook understanding of Hawking radiation involves Bogoliubov transformations. The idea is that when you quantize lets say the electromagnetic field you take solutions of the classical equations (Maxwell's equations) and write them as a linear combination of positive-frequency and negative-frequency parts.  Roughly speaking, one gives you particles and the other gives you antiparticles. Thus the way we choose the vacuum in our theory plays a strong role in the number of particles and the antiparticles. Outside the event horizon, the choice of vacuum is different and as a result we see a Hawking radiation due to particle production.
A: Hawking radiation occurs at pair production distances, the statistical probability of pair production at distances greater than subatomic are near zero.  Therefore the vast, overwhelming majority of all hawking radiation effects are produced at subatomic distances from the event horizon. at distances where the time dilation is very near infinite.  Alternately, from the reference frame of an observer at subatomic distances from the even horizon viewing the hawking radiation particle (say, a photon) the entire universe is so very very far away that it takes thousands of light years (of distance) to move through condensed space (around the event horizon) and this massive distance, from the perspective of the distant outside observer appears to be only several atom-thicknesses.  This means that the dilated rate of radiation release would never allow a black hole to evaporate.
