# Two charged black holes in equilibrium

Consider a pair of (possibly rotating) charged black holes with masses m1, m2 and like charges q1, q2. It seems that under certain conditions gravitational attraction should exactly cancel electrostatic repulsion and a stationary spacetime will result.

What are these conditions?

The point charges analogy suggests the equation

k q1 q2 = G m1 m2

However, it is by no means obvious this equation is the correct condition except in the large distance limit. Also:

Is it possible to write down this solution of Einstein-Maxwell theory in closed form?

• I think you may want to look at BPS black holes, whose charge and mass are the same (in some units). The total force between them cancels and you can have multi-center solutions. – user566 Nov 26 '11 at 21:12
• @Moshe: I know about BPS black holes but as far as I understand they only exist in supergravity. There the simple condition is indeed preserved. What I want to understand is whether the preservation of the "naive" condition is a result or supersymmetry and if it is what is the rule for ordinary gravity. But I might be thoroughly confused here... – Squark Dec 2 '11 at 17:58
• It is quite common to claim that even single black hole does not result a stationary spacetime lightandmatter.com/html_books/genrel/ch07/ch07.html – Alex 'qubeat' Dec 3 '11 at 19:00
• I don't understand what you mean. A single black hole has a Killing vector which is timelike outside the horizon. In this sense, the space-time is stationary. – Squark Dec 4 '11 at 21:52

There is a quite instructive paper G. A. Alekseev and V. A. Belinski, Equilibrium configurations of two charged masses in General Relativity, Phys.Rev. D76 (2007) 021501; arXiv:0706.1981 [gr-qc], e.g. they mentioned a work about non-existence of static equilibrium configurations of two charged black holes by P. Chrusciel and P.Tod, Commun.Math.Phys., 271 577 (2007); arXiv:gr-qc/0512043 and found condition for equilibrium of two charged masses: $m_1 m_2 = (e_1-\gamma)(e_2+\gamma)$ with $\gamma = (m_2 e_1-m_1e_2)/(l+m_1+m_2)$.