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I have a question about the following page 48 from the third edition of Goldstein's "Classical Mechanics".

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I do not understand how (2.34) shows that the virtual work done by forces of constraint is zero. How does the fact that "the same Hamilton's principle holds for both holonomic and semiholonomic systems" show that the additional forces of semiholonomic constraint do no work in the $\delta q_k$?

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    $\begingroup$ Goldstein hasn't even defined what is a virtual displacement in the book. It is quite murky in describing D'Alembert's principle. I recommend reading Lectures in Analytical mechanics by F Gantmacher. It is quite mathematical but is very precise in dealing with virtual displacements. The book begins with this. $\endgroup$ Jul 28, 2016 at 16:34

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Note that the use of Hamilton's principle (a.k.a. the principle of stationary action) for systems with semi-holonomic constraints in Ref. 1 is inconsistent with Newton's laws, and has been retracted on the errata homepage for Ref. 1. See Ref. 2 for details. See also this & this related Phys.SE posts.

For starters, Ref. 1 provides a wrong (or at best an incomplete) definition of semi-holonomic constraints, cf. eqs. (2.20) & (2.20'). However, the definition itself is the least of the problems with Ref. 1.

In conclusion, the arguments of Ref. 1 pertaining to OP's specific question are based on false assumptions, and therefore rendered moot.

References:

  1. H. Goldstein, Classical Mechanics; 3rd ed; Section 2.4. Errata homepage. (Note that this criticism only concerns the treatment in the 3rd edition; the results in the 2nd edition are correct.)
  2. M.R. Flannery, The enigma of nonholonomic constraints, Am. J. Phys. 73 (2005) 265.
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  • $\begingroup$ I rechecked it again. The passage is exactly the same in the 2 edition. Maybe both 3 and 2 ed have this portion same $\endgroup$
    – Kashmiri
    Sep 15, 2021 at 17:57
  • $\begingroup$ No, there are differences. In the 3rd edition, see e.g. the second-last sentence The same Hamilton's principle holds for both holonomic and semiholonomic systems..., which is blatantly wrong. In the 2nd edition, the corresponding sentence is an if-sentence, which is not even wrong. $\endgroup$
    – Qmechanic
    Sep 16, 2021 at 7:11
  • $\begingroup$ Yes indeed. I was wrong. Thank you for the correction :) $\endgroup$
    – Kashmiri
    Sep 16, 2021 at 7:37
  • $\begingroup$ I couldn't understand your ' not even wrong'. If you don't mind can you please tell me what that means.is the second edition correct? $\endgroup$
    – Kashmiri
    Sep 16, 2021 at 7:40
  • $\begingroup$ The if-condition in the if-sentence could be false. $\endgroup$
    – Qmechanic
    Sep 16, 2021 at 8:28
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First, assume that there are no constraints then with 2.32 derive 2.34. Now, add constraints then $Q_k$ becomes $Q_k+H_k$, where $H_k$ is force of constraint We can see that the additional force terms should do no work in order to preserve 2.34 for in unconstrained motion.

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Insofar as learning Classical Mechanics is concerned, I found Taylor to be much better than Goldstein for initial forays.

A force of a holonomic or semi-holonomic constraint is one that does work only in the direction of a conserved coordinate. One way to find such coordinates is to test the derivative of the "momentum" term in the Lagrangian $\frac{dL}{dq'_k}$ (where $q'_k$ is the time derivative of $q_k$).

If this quantity is a constant, then $q_k$ is a conserved (or ignorable) coordinate, and the force in that coordinate direction is $0$ (as force is defined in Newton's Second Law as the time derivative of momentum). This coordinate is therefore eliminated from your equations of motion. The remaining coordinates $q_k$ stay in your equations, but your forces of constraint $f_c$ have no effect on their motions.

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    $\begingroup$ -1, I don't see how this answers OP's question $\endgroup$
    – Courage
    Jul 29, 2016 at 1:01
  • $\begingroup$ holonomic or semiholonomic constraint forces have no effect on the non-conserved coordinates. When summing up all the coordinates and the forces on them, the conserved coordinates disappear and the constraint forces do no work on the rest. $\endgroup$ Jul 29, 2016 at 1:34

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