# How do you get quantum Hamilton-Jacobi equation from Schrödinger equation? [closed]

I am reading "The undivided universe: an ontological interpretation of quantum theory" and cannot understand this derivation.

From the Schrödinger equation: $$i\hbar \frac{\partial\psi}{\partial t} = -\frac{\hbar^2}{2m}\nabla^2\psi + V\psi$$ They derive the quantum Hamilton-Jacobi equation $$\frac{\partial S}{\partial t} + \frac{(\nabla S)^2}{2m} + V + Q = 0$$

using the polar form $\psi = Re^{iS/\hbar}$, but I don't understand what they do afterwards.

## closed as off-topic by ACuriousMind♦, honeste_vivere, Gert, Cosmas Zachos, garypJul 28 '16 at 19:14

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I don't know where you have trouble, but it's straightforward if you just assume $R(x,t)$ and $S(x,t)$ in the form given for $\psi$ and then expand out the operations, where:
\begin{align} \psi &\equiv R(x,t)e^{i S(x,t)\hbar} \\ \partial_t \psi &\rightarrow \Big(\frac{\partial_t R}{R} + \frac{i \partial_t S}{\hbar} \Big)\psi \\ \nabla \psi &\rightarrow \Big(\frac{\nabla R}{R} + \frac{i \nabla S}{\hbar} \Big)\psi \\ \nabla^2 \psi &\rightarrow \Big(\frac{\nabla^2 R}{R} + 2\frac{\nabla R}{R} \cdot \frac{i \nabla S}{\hbar}+ \left(\frac{i \nabla S}{\hbar}\right)^2 \Big)\psi \\ \end{align} divide through by $\psi$ and you can separate the Schrödinger equation into real and imaginary parts to get two independent equations:
The first equation is the one you seek, where I've written $Q$ explicitly.