I have a planar geometry capacitor, connected to a battery that supplies V volts. Initially there is vacuum/air in between both plates.
Afterwards, some dielectric material is inserted in between both plates, filling the capcitor as follows, with the green thing being the dielectric :
I am asked to compare the initial and final electric fields. The plates are never disconnected from the battery.
My question is the following: Should the charge of each plate be the same in the initial and final states?
My thoughts on it: Since the plates are never disconnected, the voltage will remain constant, and so Qf/Cf=Qo/Co. Since i put some dielectric, as far as i understand, Cf should be higher than Co, and so Qo should be proportionally higher than Qf. Also, based on Spirko's answer here, the battery will change the charge in the plates to mantain the voltage.
Is this correct?