I am going through Faist's Quantum Cascade Lasers book.
In the first section of the fourth chapter, he asserts that (in the context of a perturbative analysis of electronic transitions) the following can be shown: $$\langle\chi_n|p_z|\chi_m\rangle = im_0\omega_{nm}\langle\chi_n|z|\chi_m\rangle$$ Using: $$H_0=\frac{p^2}{2m}+V(r)$$ $$[z,p_z]=i\hbar.$$
Here is the progress I've made, but I seem to be proving myself into a circle.
$$\langle\chi_n|[H_0,z]|\chi_m\rangle = 0$$ $$0=\langle\chi_n|H_0\,\,z|\chi_m\rangle-\langle\chi_n|z\,\,H_0|\chi_m\rangle$$ $$0=\langle\chi_n|\frac{p^2}{2m}\,z|\chi_m\rangle+\langle\chi_n|\,V(r)\,\,z|\chi_m\rangle-\langle\chi_n|z\frac{p^2}{2m}|\chi_m\rangle-\langle\chi_n|z\,\,V(r)|\chi_m\rangle$$ Let V(r) be slowly varying (dipole approximation.) $$0=\langle\chi_n|\frac{p^2}{2m}\,z|\chi_m\rangle+V(r)z_{nm}-\langle\chi_n|\,z\,\frac{p^2}{2m}|\chi_m\rangle-V(r)z_{nm}$$ $$0=\langle\chi_n|\frac{p\,p\,z}{2m}|\chi_m\rangle-\langle\chi_n|\frac{z\,p\,p}{2m}|\chi_m\rangle$$ $$0=\langle\chi_n|\frac{p\,z\,p-pi\hbar}{2m}|\chi_m\rangle-\langle\chi_n|\frac{z\,p\,p}{2m}|\chi_m\rangle$$ $$0=\langle\chi_n|\frac{z\,p\,p-i\hbar p-pi\hbar}{2m}|\chi_m\rangle-\langle\chi_n|\frac{z\,p\,p}{2m}|\chi_m\rangle$$ $$0=\langle\chi_n|\frac{-i\hbar p-pi\hbar}{2m}|\chi_m\rangle$$ $$0=\frac{-i\hbar}{2m}\langle\chi_n|p-p|\chi_m\rangle$$ $$0=0$$
EDIT 1:
I believe the term $\omega_{nm}$ should be coming from the transition energy: $$\langle\chi_n|H_0|\chi_m\rangle = \hbar \omega_{nm}$$