# Horizontal Velocity of a Projectile thrown from a Cliff [closed]

If I were to throw a rock of a cliff at 12 m/s as a horizontal velocity, what will the final velocity of the rock become when it hits the ground? I am tempted to say 12 m/s because the horizontal portion is independent of vertical but it doesn't make sense that way.

For the horizontal portion, there is no acceleration, initial velocity is 12 m/s and final, I have no idea. For the vertical portion, acceleration is -9.81 m/s/s (gravity), velocity is 0 m/s?

## closed as off-topic by ACuriousMind♦, user36790, Diracology, garyp, John RennieJul 25 '16 at 16:49

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• It's going to depend on the height of the cliff. You are right though, the horizontal component of the velocity will remain 12 m/s - assuming no effect from air resistance. – M. Enns Jul 25 '16 at 1:12
• @M.Enns Can you explain why the horizontal velocity won't change? Gravity makes it go down faster, so doesn't that mean that it will slow down horizontally? – Imagine Dragons Jul 25 '16 at 1:22
• There's no force in the horizontal direction. – M. Enns Jul 25 '16 at 1:23
• @M.Enns If the cliff was 20 kilometres deep and I threw it at 12 m/s, it would continue at the same rate until it reaches the bottom? – Imagine Dragons Jul 25 '16 at 1:31
• That's right. Why wouldn't it? – M. Enns Jul 25 '16 at 2:10