If i hit a tennis ball 'properly' on the stringing, does it go further than if i rotate the racket 90 degrees in my hand and hit the ball with the same force, but on the side of the frame? I'm assuming I'm good enough to hit the perfect shot in each case!

Arguments for and against range from 'better' elastic energy from the stringing, to greater compression of the tennis ball due to the side of the racket providing a smaller contact/surface area.

  • $\begingroup$ i think it should also depend on the compressibility of the ball as well. $\endgroup$ – Lelouch Jul 18 '16 at 13:51
  • $\begingroup$ It would seem like suggest the softer strings would absorb more energy than the frame $\endgroup$ – Confluence Mar 10 '17 at 7:16

Will a tennis ball go further if i hit it with the side of the racket?


You want the racket to deform, not the ball. This means using the strings to elastically store energy and return it to the ball.

The Ball

The ball's deformation upon impact is undesirable because "a tennis ball is required by the rules of tennis to dissipate a fraction of the energy it absorbs when it deforms against a hard surface" [2]. More specifically, a ball dropped from a height of 100 inches is required to bounce back to within 53% to 58% of its original height [3]. To minimize the energy lost by the ball's deformation, a large fraction of energy should be absorbed by the racket frame and strings.

The Strings

Unlike the tennis ball, the strings store energy by deforming. Due to their high elasticity, the strings recover from deformation about five times more quickly than the massive racket frame, allowing a greater efficiency in returning the stored energy back to the ball - almost all of the energy stored in the strings eventually returns to the ball.

Tennis players may select a desired string tension. A lower string tension translates into greater stiffness in the string plane and greater deformation upon hitting the ball. In other words, lower tension gives the player more power. "There is, of course," wrote Howard Brody, a professor of physics at the University of Pennsylvania, "a point of diminishing returns. After all, you can't play tennis with a butterfly net. When the strings start moving and rubbing within the string plane, you begin to get serious energy loss" [3]. Generally, an acceptable range of tension is specified somewhere on the racket frame; as long as the string tension lies within this range, there is no need to worry about diminishing returns.

The Quest for the Perfect Racket: Advances in Tennis Racket Design

  • $\begingroup$ RedGrittyBrick - Unless there are any objections, this seems like the best approach to solving this problem. It's a shame I was on the other side of the argument, but i shall admit my defeat and move on! Thanks for your help :0) $\endgroup$ – 3-14159265358979323846264 Jul 19 '16 at 12:37

Here's some tennis racket physics from Rod Cross, including links to several Am. J. Phys articles (the physics educators' journal, thus excellent for learning from) and this excellent diagram:

sweet spots on a tennis racket

There are at least three "sweet spots":

  • The node, at the center of the strings, is a point where the natural standing waves in a vibrating racket don't have any amplitude. Striking the racket here can store no energy in vibrations of the racket itself, leaving more energy available to return to the ball.

  • The "center of percussion." Striking the racket here causes it to rotate about the end of the handle. If you're holding the racket at the end of the handle, it therefore rotates about your hand, rather than rotating about some other point and jerking your hand along. Note that as you choke up on the handle, the relevant "center of percussion" moves towards the throat of the racket.

  • The "best bounce" and "dead spot" zones seem to be mirrors of each other about the node. If the racket is clamped at the end of the handle a ball dropped on the dead spot will stop without bouncing --- a Newton's cradle-like momentum transfer. Cross suggests that when serving, hitting the ball at the dead spot will transfer all of the racket's momentum to the ball: stationary ball + moving racket $\to$ moving ball + stationary racket. But when returning a serve, by applying time-reversal symmetry, hitting the ball at the dead spot will cause the ball to stop and drop at your feet.

You're proposing turning the racket and hitting the ball with the frame: essentially, using the racket as a bizarrely-shaped bat. Bats have their own sweet spots: nodes for the first (and higher) bending modes of vibration in addition to the center of percussion:

oscillations in a baseball bat

The third mode of excitation in this figure is present only in hollow bats. You'll have something similar in the vibrations of the oval part of your racket. Consider the trampoline effect that makes aluminum bats more forgiving than wooden bats:

Studies have shown that a good player, who consistently makes contact with the ball at the sweet spot of the bat, can hit a ball just as far or perhaps a little farther with a wood bat as he can with an aluminum bat. The trampoline effect comes into play for poor hits away from the sweet spot. [...] As a result a ball hit by an aluminum bat will usually go farther than a ball hit by a wood hit.

The amount of reasoning which I have elided above (at the ellipsis) makes me think that your question can only be answered in the ideal case based on numerical computations, depending on the springiness of the strings and the stiffness of the racket, both in its designed and its not-designed configuration. It might make a fun undergraduate semester project.

In the non-ideal case the argument after the ellipsis wins out: you're better off hitting the ball on the strings, because trying to hit on the frame you'll have a batting average like a baseball player. Right now the best professional hitter is Daniel Murphy, with a 0.350 batting average, though I doubt the variation among the top ten or twenty is statistically significant. But if you whiff two of every three tennis balls that comes at you, it doesn't matter how far they go: your opponent can volley, and you're screwed.

  • $\begingroup$ Although this is includes a lot of material, I don't think it answers the OP's question : Will the ball go further if hit with the side of the racket? $\endgroup$ – sammy gerbil Jul 19 '16 at 9:58
  • $\begingroup$ I think the question "which ideal is better" depends on the oscillation modes of a tennis racket hit on the side. Modeling those is beyond the scope of an SE answer for me, and I don't have a tennis racket of my own to make measurements, so this is as far as I can get. Sorry to disappoint. $\endgroup$ – rob Jul 19 '16 at 11:20
  • $\begingroup$ @rob Nice detailed answer, thanks! sammy is right though, i was hoping for a definitive 'one or the other', but that certainly does not diminish your excellent response :0) $\endgroup$ – 3-14159265358979323846264 Jul 19 '16 at 12:10

To impart certain amount of kinetic energy to tennis ball you will have to do work on it. Now, work done= Power x Time. The difference between hitting using netting and hitting sideways is that, in the former case you have more contact time with the tennis ball available, so you need smaller average power to do necessary amount of work. When you hit sideways, contact time available is less, so to do certain amount of work, you need higher average power. If required power is beyond your capability, then you will end up doing less work and therefore less amount of kinetic energy is imparted to the ball. Of course you can't make the netting too slack thinking that it will thus increase contact time and therefore must be better, because then the netting will loose its "stiffness" (I am not sure what is the right word here), its ability to bounce the ball.


Interesting indeed...

My guess is if you hit the ball on the frame it should go farther. Here's my thinking: Hitting with the frame causes all the compression energy to go into the ball. The frame does not compress at all. Hitting on the stringing causes both the ball and strings to compress, which expends more energy than compressing the ball alone. The more energy that goes into compressing the stringing, means less that can go back into the ball on its return.

I imagine, the designers of the racket built it so that the strings do not provide maximum hitting power, as that would be too uncontrollable. They were probably designed to absorbed some of the impact and return the ball in a slower, more controlled manner.

This is just my opinion in the name of discussion, however. Feel free to rebuke or agree! :)

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    $\begingroup$ Well ... answers are supposed to be answers by people who at least claim to know enough about the topic speak with some authority. These posts are not meant to be entries in a discussion; in fact, this is explicitly not a discussion site. $\endgroup$ – garyp Jul 18 '16 at 14:39
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    $\begingroup$ @garyp I've a bachelors is Physics, and while it's not in tennis physics specifically, I think I'm well within my rights to voice my opinion. The original poster, isn't asking a question for their homework, or even explicitly asking for mathematical answers, so I'm not misleading in my opinion. I feel like this site, and specific question is exactly discussion oriented. I'd rather have a scientific discussion than leave this question hanging in the boards. $\endgroup$ – Garrettfromhp Jul 18 '16 at 14:54
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    $\begingroup$ @RedGrittyBrick Your first quote should be directed at the Poster, not me. All I have done is try to add my opinion to a question that had no other answer. It's difficult to throw in some factual matter when the question asked is not a conventional one. I could insert some conservation of energy equations, but as I doubt there are any related to racket verses frame mechanics (barring some over the top equations), I thought it appropriate to have a short discussion. $\endgroup$ – Garrettfromhp Jul 18 '16 at 16:26
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    $\begingroup$ My comment is not a reflection on you. It's intended to help you understand what this site is about, how it works, etc. Opinions are expressed in comments. Answers are expected to come from "experts", who can provide a definitive answer. Practically the first thing on the help page is "This site is all about getting answers. It's not a discussion forum. There's no chit-chat." $\endgroup$ – garyp Jul 18 '16 at 17:16

protected by Qmechanic Jul 19 '16 at 12:52

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