I am slightly confused on the physics of direct electric circuits. Here is what I have been taught:
- Batteries (sources of emf) provide a constant potential difference between its terminals;
- Electrons (charge carriers) gain a potential difference by being forced by the emf to go from the positive terminal to the negative terminal;
- If the battery is attached to a closed circuit, the battery having a potential difference by definition means an electric field exists in the wires of the circuit; (x )
- Electrons from the negative terminal of the battery enter the wire, but the electrons already in the wire itself also move due to the presence of this electric field. The circuit is electrically neutral, however, because the same number of electrons entering the circuit are also exiting the circuit into the positive terminal.
If the above is true, something is bothering me. I have seen graphs of voltages through different parts of a circuit, indicating that potential difference is gained from the electron passing through the battery, then in the wire the voltage is constant, then decreases when passing through a load. But this seems odd to me; if there is an electric field in the wire, then there should be equipotential lines through the wire, which would mean that the electric potential of the electron would change, not remain constant, through the wire. Textbooks I've read tend to indicate that the electrons only gain their energy when they pass through the battery, but not inside the actual circuit itself (until it is lost through a load). This would mean there is no field in the wire... but if there were no field in the wire, a current would not exist. Can someone shed some light on this? Thanks.