Consider the spin of a neutron in a magnetic field $\vec{B}$. A neutron is a neutral particle with the mass of a proton and the spin $\frac{1}{2}$. The Hamiltonian is
$H=\mu_n\vec{S}\cdot\vec{B}$ ,
whereas $\mu_n$ is the magnetic moment of the neutron. Consider a constant magnetic field along the z-axis. Thus the Hamiltonian is
$H=\omega S_z$ with $\omega=\mu_n B$.
a) What are the eigenvalues and eigenstates of the system?
b) At t=0 the system is in the state
$\left|\alpha(t=0)\right>=\frac{1}{\sqrt{2}}\left|+\right>+\frac{1}{\sqrt{2}}\left|-\right >$
$\left|+\right> =\left|j=\frac{1}{2},m=+\frac{1}{2}\right>$ and $\left|-\right>=\left|j=\frac{1}{2},m=-\frac{1}{2}\right>$.
Use the time-dependent Schrödinger Equation to get $\left|\alpha(t)\right>$.
I'm studying for an upcoming exam on QM and this is one of the exercises I'm doing dealing with right now.
a): I don't know how to start this. My general approach when I get the Hamiltonian in a problem is to write down the Schrödinger Equation.
$H\psi=E\psi$
In this case $\omega S_z\psi=E\psi$. Since $\omega S_z$ is not really an operator it means that $\omega S_z$ is already the eigenvalue? Not really sure about the eigenstates.
b) I don't know how one would get $\left|\alpha(t)\right>$ from using the Schrödinger Equation. Usually my approach to find a unitary operator and get it from $U\left|\alpha(t=0)\right>=\left|\alpha(t)\right>$ since $\left|\alpha(t=0)\right>$ is already given. Do I get the unitary operator by solving the corresponding Schrödinger Equation?
Sorry for my dumb rumblings, I'm not comfortable using the dirac notation with the Schrödinger Equation. I don't know what the problem is. I can solve the Schrödinger Equation when there's a typical problem involved and the wave function is a function and not something like $\left|\alpha(t=0)\right>=\frac{1}{\sqrt{2}}\left|+\right>+\frac{1}{\sqrt{2}}\left|-\right >$ . When I first solved the Schrödinger Equation for the potential well problem I thought I had the hang of it, but when I see this type of problem I just can't come up with any approach.