# CP violation in B meson system through mixing

Mathematically, $\left|\Gamma_{12}\right|<<\left|M_{12}\right|$ implies $\left|q/p\right|=1$,i.e there is no CP violation due to mixing. Please explain why it happens beyond this mathematical reason.

• It might help you get more responses if you could remind us non-beauty people what you mean by $\Gamma,M,q,p$ – rob Jun 13 '16 at 4:39