a). Water is flowing through a pipe of two circular cross- sections area $A_1$ and $A_2$ lying horizontally as shown in figure below. The pressure difference between the cross-section $A_1$ and $A_2$ is 7500 Pascals. If the velocity of the water through cross-section $A_1$ is $3.25\ \mathrm{m/s}$, what would be the velocity of the water through cross-section $A_2$?
Using Bernoulli's Equation, I tried rearranging the equation so that it can be used to answer a problem like the one above. $$P_1 + \rho gh_1 + 1/2 \rho v^2_1 = P_1 + \rho gh_2 + 1/2 \rho v^2_2$$ Height is constant. Therefore equation will be: $$P_1 + 1/2 \rho v^2_1 = P_2 + 1/2 \rho v^2_2$$ My question: Since the pressure is constant, will $P_1$ and $P_2$ be removed from the equation?