One can rationally ask what one could possibly see from 27 light-years away. Assuming that spacetime is neither grainy nor foggy (something that it very possibly is), it's mostly a matter of the size of the telescope and how well the scene is lit. One square meter of ground on Earth (roughly the area of a human sized "pixel", if we are generous and account for an obese population...) reflects approx. $10^{22}$ photons per second into the $2\pi$ solid angle above it. How much actual area is that? Well, it's
$A=2\pi\times(27)^2 ly^2\approx4600 ly^2$.
A light-year, on the other hand, is
$1ly\approx 365 d/y\times 24 h/d \times3600s/h \times 300000km/s\approx9.46\times 10^{12}km$.
If we substitute that into our estimate for the illuminated area, then we find that our $10^{22}$ photons/s get distributed over roughly $A=4\times 10^{29} km^2$. This means that, on average, each square meter size "pixel" on Earth produces one possible photon detection event every $400000s$ in a $1 km^2$ telescope at this distance. That's about once in five days...
So unless we want to stand very still for the duration of months or years, we need to assume that the telescope looking at us has millions of $km^2$ in optical aperture, just so that it can collect enough photons to pick us out from the background. To have enough photons to shoot an identifiable movie of a birth would take several orders of magnitude more than that. One really starts to wonder who will pay for a scientific instrument of maybe a hundred million square kilometers (roughly half the diameter of Earth, I believe) or more, does one not?
PS: This is just for sensitivity, the actual, diffraction limited optical aperture for this kind of resolution would probably have to be the size of the solar system.