# Why can't electrons absorb any energy (i.e. absorb some energy of the photons necessary and emit the residual)?

Recently I had a question in mind about the absorption of photons. Why is it that only specific energy levels can be absorbed by electrons? I mean, I get the idea that electrons in an atom have only discrete energy levels and it does seem logical that it would only absorb photons with an energy corresponding to an energy difference in the atom.

But consider this: Let's say a photon has an energy value of 10eV and the electron needs let's say 7eV for an absorption. Why can't the electron just take the necessary 7eV and the residual (i.e. 3eV) energy of the photon will be used to emit a photon with that residual energy?

I tried researching on that question on my own and I found some reddit posts saying that it has something to do with the broadening of the frequency (i.e. spectral width). But doesn't really convince me.

• Google Raman scattering. – Lewis Miller May 22 '16 at 14:05
• @LewisMiller I've read the Wikipedia entry and the hyperphysics one on it, but I don't see how this answers my question. – Rab May 22 '16 at 14:35
• This is sort of what happens in the photoelectric effect. When the energy required to dislodge an electron is exceeded by an incoming photon, it ejects the electron, and the energy difference between this threshold and the photon's is transferred to the electron's kinetic energy. In this scenario, the electron can absorb any energy above that threshold. – Kyle Arean-Raines May 22 '16 at 16:53
• Raman scattering is indeed exactly the process you are describing, whether or not that is clear from the wiki article. Check out: physics.stackexchange.com/questions/38459/… and other questions here about Raman scattering – Rococo May 22 '16 at 17:34

Okay, so just to be clear I am going to consider processes in which a photon and an atom at some energy level go in, and the photon and atom exchange energy (and momentum) such that a photon with a shifted (either higher or lower) energy comes out, while the atom ends up in a different internal electronic state than it started in. A general diagram looks like:

where non-resonant light comes in, and causes a transition between states 1 and 2 with the outgoing photon's energy also shifted in the corresponding way. I have not showed the momentum change, but that will be determined by the energies and the geometry of the situation. I've drawn this where $E_2>E_1$, but the reverse process is also possible in which the photon gains energy.

First of all, you are certainly right to wonder why this process shouldn't be allowed. As I've mentioned in a different context, a useful way to think about many physical processes, attributed to Gell-Mann, is that "everything not forbidden is mandatory." So, when the internal atomic transition + photon shift can be accomplished in a way that conserves energy, and angular and linear momentum (and also obeys some other selection rules such as those involving parity), we should expect that it is possible. And it is!

As mentioned, these processes are normally called "Raman scattering," and are an important tool in materials science for the study of vibrational levels of materials. However, to directly address the question of charles boyant, the idea of a Raman transition is more general than this. For example, in atomic physics, Raman transitions (in a slightly different form known as stimulated Raman) are often used to go between two spin states of an atom. In this case, the polarization of the photon must change along with its energy so that all conservation laws are obeyed.

Okay, so if this can happen why did you learn that atoms can only absorb light at certain frequencies that correspond to atomic transitions? There were probably two motives behind this simplification:

1. Although Raman processes are allowed, they generally occur with very low probability compared to absorption near a resonance, and also compared to scattering of photons without a change in photon energy. So in many cases they only have a very small impact on the overall atom-light interaction.

2. Because the photon never fully disappears, Raman scattering (as the name suggests) is normally thought of as an inelastic scattering process, instead of as a "partial absorption."

This way of distinguishing between absorption and inelastic scattering is particularly useful when comparing Raman processes to processes where the light is on resonance with an atomic transition. This would be the case, for example, in which the light is resonant with the 1->E transition, and the atoms can then decay both to states 1 and 2. This has a similar result to the Raman process, in the sense that photons of one energy come in and photons with a shifted energy corresponding to the difference between atomic levels come out. However, since the absorption is a resonant process, the transition strength, wavelength dependence, and actual atomic state during the process is different in these two cases.

• Nice answer, just a doubt, what forbids the process in which the photon is first absorbed, as opposed to scattered – user83548 May 23 '16 at 21:13

This answer is not rigorous, just an afterthought: Remember that a photon has to be fully absorbed first, it will not absorb and emit simultaneously. This would leave us with an electron that is momentarily in a forbidden energy state. From that state it could emit a photon to jump to what should be its correct (i.e., allowed) energy level. Uncertainty will allow some of this to happen, and will create a natural width of the lines, but it is limited to small deviations of energy, for any practical purposes. What you would need is a mechanism similar to tunneling, in which a particle can spend some time in a forbidden region. But this is also related to the uncertainty principle.

I am not aware of any tunnel-like mechanism that would allow an electron in an isolated atom to stay momentarily in a forbidden region beyond the uncertainty principle. If it exists, it is either too small to be measured or it is forbidden by some more advanced theory, such as QFT.

I didn't run any numbers, but I also suspect that the problem might be that such a decay would violate conservation of momentum. In the same way that a free electron is not allowed to absorb a photon due to conservation of momentum (the energy and momentum of a photon are related and this constraint the relationship), I also suspect (but might be wrong), that momentum conservation will work only on the allowed energy levels, so your mechanisms would violate conservation of momentum and that is why it would not possible. However, I hope an expert could give a better answer.

• Contrary to what you may have heard in popsci books, the uncertainty principle does not allow conservation laws to be violated for a short amount of time. See for example: physics.stackexchange.com/questions/103724/… – Rococo May 22 '16 at 20:54
• In addition, an inelastic transition of this kind certainly can conserve momentum, although it will in general require the atom to recoil in the appropriate direction as the photon is scattered. – Rococo May 22 '16 at 20:59
• – user83548 May 22 '16 at 21:01
• @Rococo you can make the same argument with a free electron, and we know it doesn't happen – user83548 May 22 '16 at 21:02
• @Rococo if you know the answer please post it so we can all vote it – user83548 May 22 '16 at 21:11

There is no reason you need to talk about "forbidden energy levels" to understande this. An electron is tied to an atom just like a mass on a spring. It has a specific frequency that it can vibrate at. When it is driven by an oscillating electric field at just that correct frequency, it vibrates. We say that it is absorbing energy from the field. If you drive it with a higher frequency, it simply doesn't vibrate. You need to drive it with the correct frequency. (There may be more than one correct frequency in a given atomic system.)

It's as simple as that.

I believe if an atom receives too much energy it can be ionized. There are allowed energy levels but above these levels is the region for free electrons. The energy levels there are not quantized and can receive any energy. Photons with higher energy can put the total energy above the allowed energy levels therefore ionizing the atom. Another way to look at it and I may be wrong is with blackbody radiation. The atoms may have allowed energy levels but as the material heats up all levels of the spectrum are allowed to emit photons.

• This does not answer the OP's question. – Rococo May 22 '16 at 19:27