How can I find initial and final velocity? Is there a way to find initial and final velocity if I only know the acceleration and distance and which formula must I use? I do not know the time either.
EDIT
Thank you for all your answers! You were right I didn't know enough to solve the problem. How ever it was just the first part of a two parts task. And at first I thought that the second part is even less doable since it had more unknown variables. It appears that I was wrong and I should have started from there instead.
 
This is the exercise and I solved it using a system with four equations and four unknown variables to solve it. The variables in question being Vc, Vb, t and γ. Once I found VB it was easy to do the rest.
I suck at thinking like a mathematician.
By the way this is my first question and I am not yet familiar with the etiquette of this site. Am I supposed to  delete  a question once it has come to a conclusion or leave it so others can see? 
 A: 
(Source of image: Mohsin Khan, http://cslearners.blogspot.com/2009/08/equation-of-motion.html)
Here they are! All the formulas. 
Sorry to say, you cannot find anything if you have only acceleration and distance. Think like this, Say you have an object that has an acceleration of 2 m/s^2. and if i say that if travels a distance of 2 meters. It can travel those two meters in any time period, may be 1 s or 0.23s. I HAVE TO METION time, to make sense of the statement. 
Things are very different, if they say that the object started form rest. 
A: If you draw a velocity-time graph you will see that you do not have enough information to find the initial and final velocity.

The gradient of the graph is fixed because it is the acceleration.
The distance is the area under the velocity-time graph.
As you will see from the graph you can draw an infinite number of trapeziums (or triangles) which satisfy the known acceleration and known distance condition.
The graph also shows you which additional parameter you need to define to uniquely position a trapezium.
A: Under constant acceleration, the relationships between velocity, acceleration, distance and time are:
$$\begin{align}v_t &= v_0 + a_t\\
x_t &= x_0 + v_0 t + \frac12 a t^2\end{align}$$
When a and d ($x_t$) are given, you are left with two equations and three unknowns: $v_0$, $v_t$ and $t$.
This means you cannot come up with a numerical (unique) solution, unless you have more information. Perhaps if you read the question carefully, you discover that after 1.1 m the object is stationary (is it the highest point it reaches?).
We can't guess what other information you have; but I can tell you that mathematically speaking, two equations with three unknowns do not have a solution.
A: Assuming constant acceleration
You have to know the time also. If you know the distance traveled $s$ after time $t$ then you can write
$$ s = v_0 t + \frac{1}{2} a t^2 $$ and solve for the initial velocity $$v_0 = \frac{s}{t} - \frac{a t}{2} $$
Once the initial velocity is known, then the final velocity is
$$ v_1 = v_0 + a t $$
A: No, that's not possible. Unless the body is starting or ending at rest in which case $v_f$ or $v_i$ would be zero and you could substitute in $0$ in the eq: $v_f^2 = v_i^2+2aS$
Intuitively this makes sense. If the acceleration and distance for which the body accelerates are known, you can only determine $v_f^2- v_i^2$
You don't know whether $V_i = 0m/s$ and $V_f =10 m/s$ which gives $v_f^2- v_i^2 = 100$ or if $V_i = 9m/s $ and$ V_f \approx 13.45 m/s$ which also gives $v_f^2- v_i^2 \approx 100$ or the countless other solutions. However, if you have $V_f$ or $V_i$ in this case, you can find the other.
