# Baryon / lepton number violation equivalence in Sakharov conditions

In the Sakharov conditions for matter-antimatter asymmetry the requirement for the baryon number violation is often interchanged with lepton number violation. In the context of the Sakharov conditions, how is it that baryon number violation can be equivalent to lepton number violation?

$$\partial_\mu J_B^\mu=\partial_\mu J_L^\mu \neq 0$$
From here you see that the current $B-L$ is conserved (anomaly-free) but not $B+L$.
Therefore any violation of baryon number leads in principle to a violation of lepton number by the same amount (to keep $B-L$ conserved), and vice versa. This is mediated by the so-called sphalerons. However, sphaleron transition are extremely suppressed at energies below the electroweak scale so baryogenesis via leptogenesis scenarios must go to higher scales.