# Difference between energy loss at high voltage and high current

When reading about power transmission one very common statement is that power is transmitted at high voltage to minimize loss in the form of heat.

What confuses me is the governing equation. Aren't $H=V^2t/R$ and $h=i^2Rt$ essentially the same equations with the common form $V=iR$?

Won't a potential difference of $22000\ \mathrm{V}$, with a resistance of $1\ \mathrm{k\Omega}$, produce a $22$ ampere current, with the heat dissipated the same as if I had used a higher current on a smaller voltage? Thanks.

• $i=\frac{P}{v}$ Increase voltage, decrease current for same power, current causes the heat loss. – Feyre May 14 '16 at 14:23