71
$\begingroup$

Why does a system like to minimize its total energy? For example, the total energy of a $H_2$ molecule is smaller than the that of two two isolated hydrogen atoms and that is why two $H$ atoms try to form a covalent bond. According to the classical mechanics, it is the potential energy of a conservative system that is minimum in equilibrium, not the total energy.

$\endgroup$
3
  • 12
    $\begingroup$ Actually it's the free energy that's minimised :) $\endgroup$
    – lemon
    Commented May 11, 2016 at 20:39
  • 4
    $\begingroup$ Entropy of a system always increases. If there is energy available to do work, that availabe energy will tend to be "used up" and lead to a highr disordered state. $\endgroup$
    – Peter R
    Commented May 11, 2016 at 20:46
  • 1
    $\begingroup$ This is your most popular question and there are a number of highly rated answers. Why have you not accepted any of them? $\endgroup$
    – kaylimekay
    Commented Dec 28, 2020 at 12:34

5 Answers 5

93
$\begingroup$

The anthropomorphic formulation "tries to" is misleading. Under the effect of ambient noise, matter explores the possible configurations around its current state: e.g., two single hydrogen atoms wiggle around and meet. If they happen to bind, this releases energy which goes away, and we say that the energetic state of this new $H_2$ molecule is lower than what we had. Unless the ambient noise or some experimentalist gives back this energy to the $H_2$ molecule, it will stay so, so there is a net bias toward these states that we describe as having a lower (free) energy.

Let's add that the traditional way to explain this bias (meaning that you need more energy, and thus have less chances, to move from a lower energy state to a higher one than the other way around), is with this schematic of a potential energy analogy:

enter image description here

$\endgroup$
6
  • 2
    $\begingroup$ Very enlightening answer - thank you. Alway sort of wondered at this in the back of my head. $\endgroup$
    – Mike Wise
    Commented May 12, 2016 at 8:20
  • 44
    $\begingroup$ I like how you warn that anthropomorphic "tries to" is misleading and then talk about how matter "explores" possible states. Nice answer anyway :) $\endgroup$ Commented May 12, 2016 at 11:40
  • 4
    $\begingroup$ I believe the " If they happen to bind, this releases energy which goes away" is also at the heart of the matter and can only be explained with the 2nd law of thermodynamics, as is done below by @valerio92 . $\endgroup$
    – hyportnex
    Commented May 12, 2016 at 12:58
  • 17
    $\begingroup$ @Joce I don't think it made your question misleading, just that it was funny how hard is it to actually avoid anthropomorphism. $\endgroup$ Commented May 12, 2016 at 13:02
  • 2
    $\begingroup$ @hyportnex: as I understood the question, it was rather about why the process ends up finding the energy minimun, rather than how energy varies upon specific events. That's why I've stayed at this level of detail. $\endgroup$
    – Joce
    Commented May 12, 2016 at 13:06
25
$\begingroup$

This is a consequence of the second law of thermodynamics, which states that

In a closed system with fixed internal energy (i.e. an isolated system), entropy is maximized at equilibrium.

It can be shown that this statement is equivalent to the following:

In a closed system with fixed entropy, the energy is minimized at equilibrium.

Callen in his book gives the following argument (chapter 5):

Assume that the system is in equilibrium but that the energy does not have its smallest possible value consistent with given entropy. We could then withdraw energy from the system (in the form of work) maintaining entropy constant, and we could thereafter return this energy to the system in the form of heat. The entropy of the system would increase ($\delta Q = T dS$), and the system would be restored to its original energy but with an increased entropy. This is inconsistent with the principle that the initial equilibrium state is the state of maximum entropy! Hence we are force to conclude that the original equilibrium state must have had minimum energy consisted with the prescribed entropy.

$\endgroup$
21
$\begingroup$

This is really a statistical effect, as pretty much all of thermodynamics.

You have two free hydrogen atoms. They tend to move around the space they have, and when conditions are favourable (there's enough energy, the atoms come "close enough" together), they might interact - chemically or otherwise.

Now, "enough energy" is the important bit here. When a hydrogen atom meets another hydrogen atom, they have a lower energy state available. That is, without adding any external energy (e.g. from the relative motion of the two atoms), there is another state they can occupy (the hydrogen molecule) while releasing energy to the environment (usually as EM radiation).

This escaping energy is the thing that prevents the reaction from running "backwards". And since there's a non-zero chance of the reaction occuring, and a much lower (zero in our simplified case) chance of the reverse reaction occurring, we can observe that the system "minimized its energy".

In reality, most reactions run in both directions simultaneously and many different reactions occur in the same mix of chemicals. For example, carbonated water will tend to have ongoing reactions that convert water and carbon dioxide to carboxylic acid and vice versa - the concentration of the acid will tend toward an equillibrium where the forward reaction and the reverse reaction happen at the same rate. But they're still happening. However, note that this happens because the system not only loses energy, but gains it as well - the equillibrium happens when the amount of outgoing energy is equal to the amount of incoming energy. If that's not the case, the reaction becomes non-reversible over time as total energy is lost to the environment.

This applies to all thermodynamic systems. Imagine a ball bouncing off the ground. If the bounce is perfect, no energy is dissipated to the environment, and the ball will keep bouncing forever - it will just keep changing kinetic energy to gravitational potential energy and vice versa. There's no "minimization of total energy" - the energy of the system is simply conserved. But as thermodynamics teaches us, you can't make a system that's perfectly closed. And as soon as energy starts to "escape" the system, you'll find the ball starts bouncing lower and lower until it comes to rest. The energy was lost to heat, sound etc., and is no longer available to push the ball back up.

$\endgroup$
15
$\begingroup$

I'm going to take a slightly different approach and say it's because we defined energy to make it so. In other words, systems "try" to find the lowest energy state because energy is a concept humans invented in order to describe what we observe.

This is the reason that for any given set of constraints, you might need a different "energy" to describe the behavior of the system. In quantum mechanics, it works out that what we call energy (as given by the energy operator) is minimized. In classical mechanics, we refer to potential energies to distinguish between the myriad other types of energies that can be defined for a system, and choose definitions for them so that the potential energy (gravitational, thermodynamic, etc) is minimized.

In the end, what it means is that for a given state of the system, you can define a function that gives you a value relative to a lowest energy (ground) state. We define this function in such a way that it tells us which state is more likely to occur, and we do this by observing physical laws.

In that sense, it is a little bit backwards to say that a system "tries" to reach a minimum in energy (ignoring the problems inherent to anthropomorphism), since the system is just doing what it does, and we are using energy as a way of understanding that.

$\endgroup$
1
$\begingroup$

Energy is a secondary concept, at least in Newtownian mechanics, so let's start with the fundamentals.

There exists a force field. A gravitational one, say. An object in this field feels a force. This force "wants" to make the object accelerate.

From forces, define work as $force \times distance$ and now we can give precise mathematical meaning to the intuitive concept that "it takes work to lift this ball from the floor to the table".

From work, define energy. Energy is how we keep track of all the work that we did. When we say "the ball has $x$ Joules of kinetic energy" that's a way of saying "some force acted upon the ball, doing $x$ much work, and now because of that force the ball has accelerated to the given velocity".

So let's answer the question: "why does a system like to minimize its total energy?" First we have to clarify the question, we have to nitpick about what "the system" is because when lifting a ball from the floor to the table I have apparently increased its energy, contradicting the premise. I think you mean "why does a system like to minimise its potential energy?" Potential energy exists because the force exists -- the ball potentially will fall back to the floor, if it is allowed to; gravity will do work on the ball as it falls and this will manifest as kinetic energy. So saying "the ball wants to minimise its potential energy" is basically saying "the force of gravity exists".

But if the ball actually is allowed to fall, we're trading potential energy for kinetic energy, and the total energy of the system is constant. If it bounces with perfect elasticity and there is no air resistance etc, it will return to its initial configuration: no energy change. In practice, the bounce will be slightly elastic, work will be done agitating the molecules into motion (heat, sound, etc) and so not all the energy will be returned to the ball in the bounce, so the energy of the (no longer closed) system will tend to decrease.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.