Assuming all surfaces to be frictionless. If the mass of the inclined plane is large enough, could $N$ ever be equal to $mgcos\theta$. Reasons?
So far I've come up with: $mgcos\theta - N = ma$ meaning if N were to equal $mgcos\theta$, $ma = 0$. Since the surfaces are frictionless and since N is acting on the inclined plane too(it'll have a horizontal component), this isn't possible. Am I right? Where am I going wrong?