There's nothing probabilistic when it comes to Conservation of Energy, and Quantum Mechanics. In fact, many equations from QM and Special Relativity are derived by first assuming Conservation of Energy. So, energy will be conserved, no matter what, by definition. The Schrodinger Equation itself is derived by saying "Here's a wavefunction, let's assume energy is conserved". And $E=mc^2$ is what what you get when you say "Let's measure Doppler shift, but assume energy is conserved".
However, in the QM case, energy is no longer the $\frac{1}{2}mv^2$ you may be used to, since $m$ and $v$ can be in superpositions. The energy of the system is encapsulated by what is called the "Hamiltonian Operator", and the statement of the Schrodinger Equation is that the Hamiltonian Operator of the Wavefunction remains conserved over time. You can read more here. The equation boils down to, if a particle can be in energy states 1, 2, and 3, then we know that P(1), P(2), and P(3), do not change over time (P(x) being the probability of energy state x). An Energy State can be described by $KE + PE$, where $KE$ is only dependent on your momentum, and $PE$ is dependent only on time and position. (More precisely, we have an "Energy Operator", which is what we call the Hamiltonian because that's what we presume is conserved. We could throw any conservation law in there, and get various results. Generally, $KE$ is set to the familiar $\frac{1}{2}mv^2$, and $PE$ is dependent on the force you want to model.)
So, in a purely Quantum environment, energy by this definition is neither created nor destroyed.
It's possible the universe started out in a superposition of energy states, and this remains consistent with current theories. But, we are a part of the universe, and trying to consider superpositions of conscious beings gets very weird from a philosophical perspective. So for our story let's assume for now that the big bang just happened and our macroscale bodies exist in a deterministic universe that started with a total energy E, with no Wavefunctions anywhere.
Let's say we decide to shoot two protons at each other with total energy $v$. Now, our deterministic part of the universe has energy $E - v$, and our protons have energy $v$ (With $v$ high enough to be interesting). Let's say that the protons are no longer a part of the deterministic side of the universe, so that they begin to experience quantum effects.
They collide, and split into many particles, through many different mechanisms (Feynman Diagrams), all simultaneously in superposition. However, from the Schrodinger Equation, we know that total energy of the Wavefunction after our experiment must equal $v$, with probability 1. After the protons collide, we no longer have one neat Wavefunction. We have a weighted sum of the Wavefunctions of each possible collision result.
In this case it's not so bad, since we know that each possible collision will also have energy $v$ (By Schrodinger). But, the collision resultant particles will have unknown energy levels (Since post-collision they are now their own closed system, we can consider each resultant particle to have its own wavefunction). Say our experimental results show that the proton split into one new particle with an energy of E1, and another particle with an energy of E2. I say "With an energy of", but what I really mean is that their wavefunction could be something like a normal distribution around E1 and E2, respectively (With the exact curve being a result of Schrodinger's Equation). What we know for a fact is that $E1+E2$ approaches $v$ as our measurements of E1 and E2 grow more and more accurate. It's important to realize here that energy conservation occurs via entanglement, since if a measurement of E1 is unexpectedly large, then E2 must be unexpectedly small, regardless of whether or not we measure it or care about its existence. (Ie, it will be small when it collides with air particles to distribute its energy, while our scientific devices observe E1 being large)
In our story, the results from our initial collision and all subsequent collisions will entangle, via the method described above, with the rest of our measurement apparatus and eventually the universe, so that everything at the quantum-scale becomes a mess of wavefunctions and superpositions of various energy levels. It does remain that the genesis wavefunction, and thus the global wavefunction over time, still has an explicit total energy $E$. The more precisely we try to measure the energy of everything, the closer we get to calculating that genesis $E$.
In reality, we did not get to measure the universe before the initial wavefunction. We can presume that the instant the big bang happened, the very first wavefunction happened. So we just don't know what $E$ is. We don't even know it exists, since there may be many $E_i$, as discussed earlier. For sanity, I like to presume there is indeed a genesis $E$ (Copenhagen does allow us to assume that macroscale objects do not exist in a state of superposition, and "The Entire Universe" is indeed macroscale). We can't calculate $E$ exactly, but we know that the sum of the energies of all things that we measure will never deviate from $E$ by any more than our own measuring instruments allow, no matter how lucky or unlucky we are.
P.S.
Maxwell's Demon, as mentioned previously, makes no claim to violate conservation of energy. What it attempts to violate is the 2nd law of thermodynamics. There's nothing that prevents pure luck from causing all the atoms to collect on one half of a box, and in-fact the 2nd law of thermodynamics is inherently probabilistic. The 2nd Law gives us many equations that are useful such as the ideal gas law, but these are macro-scale laws.
The 2nd Law of thermodynamics does not help us at the quantum level, and is in-fact entirely irrelevant. It's just not a law at all on the microscale, and you can get lucky and unlucky day and night on the quantum level (2nd Law is okay with being lucky on small scales). W Bosons with mass low enough to cause atomic decay are extremely, extremely, rare, but energy is conserved even when these events happen.
On the same token, the solution to Maxwell's Demon does not show that it is impossible to isolate gas temperatures without adding energy. It shows us that Maxwell's Demon can't do so without gaining entropy on average. If we assume infinite luck, and thus a functioning Maxwell's Demon, it may seem like "Oh, I can make perpetual motion out of this". But you can't. It would definitely give you a lot more energy than previously available, since you could spin a turbine with all of the luck you have in separating hot and cold particles. However, the velocity in the particles will be lost as the turbine spins faster, until eventually all of the particles in the chamber approach absolute zero.
QM exists such that, so long as you can't generate infinite kinetic energy, there's some valid function $PE(x, t)$ to describe potential energy. Then, we deduce the conservation of energy (Or rather, the equations were built to match such an assumption).