A cylinder of mass 5 kg and radius 10 cm is moving on a horizontal surface with velocity of centre of mass 5 m/s towards right and angular speed 10 rad/s (clockwise) . Find the angular momentum of the cylinder about the point of contact.
My approach: The angular velocity of the body about the point of contact will be 10 rad/s and the moment of inertia about the point will be 1.5 MR^2 . So angular momentum should be (moment of inertia)*(angular velocity)= 10 * 1.5 (5)(0.1)(0.1) giving 0.75 but the answer is 2.75 . I don't know where I have gone wrong.