Assuming there is no wind, do two raindrops of different sizes fall at the same speed? Assuming there is no wind, do two raindrops of different sizes fall at the same speed?
Simple enough question. Look forward to your answers.
 A: I'm not sure what you mean about "assuming there is no rain" but larger raindrops do have a faster terminal speed than smaller drops.
EDIT: Here's a whiteboard video using Stoke's law to explain why.
A:  The drag force due to the atmosphere would be larger for the larger raindrop, resulting in a reduced acceleration. Therefore, the smaller raindrop would start moving faster in time. 
Eventually, you will have two rain drops falling at terminal velocity. The faster rain drop will be the one with less surface area perpendicular to the motion.
edit: Sorry, that is not entirely true. Although the larger raindrop has greater surface area ( and thus larger drag force ) it also has greater mass. So if you re-arrange,say, $F_d = \frac{1}{2}\rho v^2 C_d A = F_g = mg$ for velocity you get $$v^2 = \frac{2mg}{{\rho}(A)(C_d)}$$ where $\rho$ is density of the fluid, $A$ is surface area, and $C_d$, the drag coefficient, is $C_d \propto \frac{1}{v}$ 
The faster raindrop would be one with greater mass and less surface area perpendicular to the motion. 
