Characteristic room-temperature photon energy - is this nomogram wrong? Reading this recent ars technica article on the James Webb telescope, something kept bothering me about the nomogram - shown below. The credit says it is from The Opensource Handbook of Nanoscience and Nanotechnology. 
Is the graphic wrong, or am I missing something? I'm comfortable in rooms where kT is about 1/40 eV - this plot looks like it comes from Pluto!
Question: Approximately where on that graphic should the red room temperature line actually fall?

 A: Conversion from K to eV
Let's assume room temperature is at ~300 K, just to make the numbers easy.  To convert to electron volts, one simply does:
$$
T \ [K] \times \left( \frac{ 1.38064852 \times 10^{-23} \ J }{ 1 \ K } \right) \times \left( \frac{ 1 \ eV }{ 1.6021766208 \times 10^{-19} \ J } \right) = \left( k_{B} T \right) \ [eV] \\
\left( k_{B} T \right) \ [eV] \sim \left( \frac{ 8.61733 \times 10^{-5} eV }{ 1 \ K } \right) \times T \ [K]
$$
where $k_{B} = 1.3806505 \times 10^{-23}$ J/K is the Boltzmann constant, and $1.6021766208 \times 10^{-19}$ J/eV is an energy conversion factor equivalent in magnitude to the fundamental charge.  The values shown above are the 2014 CODATA/NIST values.

Question: Approximately where on that graphic should the red room temperature line actually fall?

Answer
So using the above we find that 300 K ~ 0.02585 eV or $\sim 3 \times 10^{-2}$ eV.  Therefore, the red line should be between the $10^{-1}$ and $10^{-2}$ tick marks on the eV scale bar, not the $10^{-2}$ and $10^{-3}$.
