# Number operator in interacting quantum field theory

When treating a quantum field, say the real scalar field, it's totally clear to me how to define a (global) number operator:

$$\hat N = \intop \text d ^3 \mathbf p \hat a ^\dagger (\mathbf p )a(\mathbf p ).$$ This turns out to commute with the hamiltonian and the 3-impulse of the system, therefore the physical interpretation of states with a definite number of particles with a definite total 4-impulse is straightforward. In particular, one could define the vacuum as $\hat N \rvert 0 \rangle =0$.

Now, consider a field interacting with itself, for example:$$\mathscr L =\frac{1}{2}\partial _\mu \phi \partial ^\mu \phi -\frac{1}{2}m^2 \phi ^2 -\frac{\lambda}{4!} \phi ^4.$$

In this case one still talks (in a sense which is not clear to me) of states with a definite number of particles. In a proof, my professor wrote, for a generic state $\alpha$:$$\lvert \alpha \rangle = \lvert \alpha \rangle _0 + \lvert \alpha \rangle _1 + \lvert \alpha \rangle _2 + ...$$where the pedices denote the number of particles in each state of the expansion. Now, this equation implicitly says that there is a certain observable $\hat N$ such that $\hat N \lvert \alpha \rangle _n = n\lvert \alpha \rangle _n$.

Question. Is there a theorem which guarantees the existence of such an operator for every physical field theory? Is it possible to construct explicitly $\hat N$?

• And interacting field theory does not have particle states, and doesn't have a number operator. Are you sure these "interacting particle states" don't like in the asymptotic Fock space instead? Mar 17 '16 at 17:56
• No, it is not always possible to construct the number operator; it depends on which representation of the CCR you're in. The canonical commutation relations for QFT admit uncountably many inequivalent irreducible representations. Technically speaking, given the algebra of the CCR and a state on it, it is possible to define a self-adjoint number operator on its GNS representation only if the state is normal with respect to the Fock representation. Mar 17 '16 at 22:21
• @ACuriousMind , I'm indeed confused about it. In the particular example I'm mentioning, those states are taken to be eigenstates of the full (interacting) 4-impulse, but since they must be also eigenstates of some number operator, from what you and yuggib say, I deduce that they must be linear combinations of Fock space $n$-particle kets. Mar 18 '16 at 11:00
• Anyway, if you or @yuggib want to turn your comment into an answer, I'll be glad to accept it. Mar 18 '16 at 11:00
• @pppqqq The point is that nobody at the moment knows what is the right Hilbert space (i.e. representation of the CCR) for any relativistic interacting QFT in $(3+1)$-dimensions. It may as well be the representation induced by a Fock-normal state, and therefore with a number operator. There are some suggestions that this should not be the case, but it's an open question. Anyways, the answer to your question is "there are representations of the CCR where it is not possible to define a self-adjoint number operator; whether these representations correspond or not to physical theories is not known" Mar 18 '16 at 14:34