0
$\begingroup$

Why must supersymmetry be broken during the inflation in supergravity models? How does adding supersymmetry to power-law or Starobinsky models spoil inflation?

And is breaking of SUSY needed for both F-term and D-term inflations?

$\endgroup$
  • $\begingroup$ Do you have a reference? I'm not sure exactly what scenario you're describing $\endgroup$ – innisfree Mar 16 '16 at 11:43
  • $\begingroup$ You can see here for example - "arxiv.org/pdf/1101.2488v2.pdf", for general cases. $\endgroup$ – Kosm Mar 16 '16 at 11:48
0
$\begingroup$

For inflation we need to have a positive energy density $V>0$, which drives inflation. If [the VEV of] the F-term potential $V_F>0$, then we necessarily have F-term SUSY breaking. (Text in [] should be removed, see discussion below.)

psm

| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ But isn't it sufficient that the inflaton has positive values during the inflation, without having a VEV? $\endgroup$ – Kosm Mar 16 '16 at 14:03
  • $\begingroup$ I don't get what you mean. Let $\phi$ be the inflaton. Then, during inflation we necessarily have $V(\phi)>0$ and SUSY is (spontaneously) broken. $\endgroup$ – psm Mar 17 '16 at 13:00
  • $\begingroup$ But what does it have to do with VEV? VEV is the value of \phi when potential is at minimum. But during the inflation the potential is not at minimum, it is located at the plateau. $\endgroup$ – Kosm Mar 17 '16 at 13:18
  • $\begingroup$ Oh, sorry. I should edit that. During inflation we have $V>0$, that's it. $\endgroup$ – psm Mar 17 '16 at 13:32
  • $\begingroup$ So, did I understand correctly that the form of the scalar potential itself is not SUSY invariant? And only when V=0, SUSY is restored (?) $\endgroup$ – Kosm Mar 17 '16 at 13:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.