How does current split in a parallel circuit? [closed]

I'm having trouble understanding why the current that goes through the 6 ohm resistor is 1A when the proportion of the parallel resistors is 2:1 from top to bottom.

Could anyone explain how current splits in a parallel circuit such as this one? Thanks in advance.

• Do you know Ohm's law? Commented Mar 12, 2016 at 2:15
• The voltage across the 6 ohm resistor is the same as that across the 12 ohm resistor, right? Just use V/R=I and to determine the currents. It should be apparent that the ratio of the currents is the inverse of the ratio of the two resistances.
– user93237
Commented Mar 12, 2016 at 2:52
• "Could anyone explain how current splits in a parallel circuit such as this one?" - of course. But is it too much to ask that you show even a small amount of effort researching this frequently asked question? Voting to close. Commented Mar 12, 2016 at 3:11
• Consider the nodes entering and leaving the set of parallel resistors: we know that the current entering the first node is equal to the current leaving the second node, and that the voltage drop has to be the same for each of the parallel resistors because they share the two nodes. Given those two constraints, and Ohm's law for each resistor, the current can only divide in one way. Commented Mar 12, 2016 at 3:21
• This was a test question to see how a community responds to an obvious FAQ, the question is now closed. Commented Mar 12, 2016 at 7:06