1
$\begingroup$

Suppose I have a string that is fixed rigidly at one end. Now when I start making wave, it will get reflected and should lead to standing waves (Mathematically and by visualization), but then we have a fixed condition that the end of the rope at the rigid wall has to be a node, while the free end has to be an antinode. That limits the wavelength to a finite possibilities, thereby defining the frequency. But, isn't frequency dependent on us? Like, I can decide how fast I will move my hand thus I decide time period and frequency, though I can't decide 'k'. So what will happen if I do so at a random frequency? Will a standing wave not be formed? What will happen? My calculations:

EDIT - I just realized that the velocity of the wave is not constant and can be changed upon change in tension. So then, will it be that For any frequency, the wave will be a standing wave, and that the only difference is that now wave velocity and tension in the rope will be different?

enter image description here

$\endgroup$
  • $\begingroup$ Why does your scenario only allow for a limited number of wavelengths? $\endgroup$ – Jaywalker Mar 11 '16 at 6:53
  • 1
    $\begingroup$ Because the distance between a node and antinode, and that between 2 antinodes is fixed, so we can't have an arbitrary wavelength for a rope, please correct me if I'm wrong $\endgroup$ – Shodai Mar 11 '16 at 7:16
  • $\begingroup$ Only certain excitation frequencies will lead to a resonance and a standing wave for a given set of string mass per length and tension. Other waves will simply not be standing, i.e have fixed node positions. $\endgroup$ – roadrunner66 Mar 11 '16 at 7:30
  • $\begingroup$ But why not? See the pic, clearly there should be many places for which the wave's displacement is zero at all times, why does that not happen then? $\endgroup$ – Shodai Mar 11 '16 at 7:32
1
$\begingroup$

You can shake your hand at any arbitrary frequency you like but standing waves only form for particular frequencies
$$f_n = n\frac{v}{2L}=\frac{n}{2L}\sqrt{\frac{T}{\mu}}$$
where $n$ is an integer. At other frequencies travelling waves move both left and right along the string. For standing waves the nodes are stationary, for travelling waves they move along the string.

The reason (as you know) is that the length of the string has to be a multiple of the distance between antinodes. The distance between antinodes depends only on wave speed $v$ and frequency $f$. If these are fixed then the distance between antinodes is fixed.

If you can change $T$ this changes $v$. Then you can get a standing wave at any frequency you choose.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.