# Why do electromagnetic waves diffract? [duplicate]

The expansion of electromagnetic waves due to diffraction can be easily explained with Huygens' principle (and in introductory courses this is usually how it is explained). But Huygens' principle is physically wrong.

What is it in the electric and magnetic field that makes light diffract? In other words why will a perfectly collimated beam of light spread out?

• On meeting a barrier there is a part of the wavelet which does not travel in the same direction as the originating wavefront. – Farcher Mar 8 '16 at 20:24
• see this. Even possibly a duplicate? – scrx2 Mar 8 '16 at 20:37
• Imagine that your "perfectly collimated beam" is only a few wavelengths in diameter. – Keith McClary Mar 8 '16 at 21:08
• – glS Mar 8 '16 at 21:42
• Suppose there would be no diffraction. Then what would define the direction the wave is supposed to travel in to infinite accuracy? – Count Iblis Mar 8 '16 at 21:56

$$\frac{\partial ^2}{\partial x ^2}U + \frac{\partial ^2}{\partial y ^2}U + \frac{\partial ^2}{\partial z ^2}U = \frac{1}{c^2} \frac{\partial ^2}{\partial t ^2}U$$
The easiest way to see why this is to consider the Fourier transform property $\frac{\partial ^2}{\partial x ^2} \rightarrow -k_x^2$. Since $k_x$ determines the degree of propagation in the x direction, this lends itself to the physical interpretation that field variation in the x direction leads to propagation in the x direction as well. For something like a laser beam to be self contained, it should go to 0 far away from the beam, but be nonzero at the beam. Hence, variation in the transverse profile, and propagation in the transverse profile as well.