Suppose I have a 50-50 mix of two different kinds of atoms in a crystal. The crystal is BCC and the atoms have different scattering factors $f$.
I know that if the crystal is organized in the regular BCC way (say, like CsCl) then I can easily calculate the structure factor. This page shows what it would be for CsCl, for example. I understand this part.
But what would happen if the crystal were still BCC but the atom locations were picked randomly? If you performed neutron diffraction on this crystal, would you be able to see any (h,k,l) planes?
My thinking is either: a) you see no (h,k,l) planes (because the disorder means that you don't know the atom locations so the calculation for the structure factor is impossible) or b) you see all planes (because there are no interference effects so all planes are equally "visible")?
I am trying to wrap my head around crystal diffraction and I'm finding this one tough to think about. This is partially a continuation of this question.