2
$\begingroup$

I've a question regarding the interpretation of the neutrinos in neutrinoless double beta decay:

1

The basic issue that I have is with papers that regard the decay as a neutrino-neutrino annihilation (as the neutrino is a Majorana particle in this case). The reason is that it can't be classical annihilation because we'd get no end-product (and therefore a loss of energy) like in electron-positron annihilation.

Now you could say "they are virtual particles so they don't lie on their mass shell", but wouldn't it then be better to avoid this annihilation interpretation completely? Another interpretation could be nucleon-neutrino absorption and isn't that a better one? This process could at least in principal (neutrino-up -> W- -> electron-down) also happen with a "lone", real neutrino.

So what I want to say is that the annihilation interpretation is at least controversial, right (apart from the perturbative character of virtual particles)?

$\endgroup$
3
  • 1
    $\begingroup$ I don't think neutrinoless double beta decay is normally treated as an annihilation. The process is that the first down quark emits a left handed neutrino and turns into an up quark while the second down quark absorbs a right handed neutrino and turns into an up quark. That's what your diagram shows. $\endgroup$ Commented Mar 3, 2016 at 12:18
  • $\begingroup$ Ah I see, as I thought it would be. So I think that the "annihilation" mentioned on wikipedia should be wrong (Along with 0vßß diagrams that show a cross in the neutrino propagator) and the process should rather be seen as a light majorana exchange in the standard solution. $\endgroup$
    – 0vbb
    Commented Mar 3, 2016 at 12:56
  • $\begingroup$ i too think that using the word annihilation here is wrong, it is plainly a an interaction mediated by a Majorana particle, which can mediate such an interaction due to the fact that it is its own antiparticle.. $\endgroup$
    – Bruce Lee
    Commented Mar 3, 2016 at 14:31

2 Answers 2

3
$\begingroup$

From the particle data group it is shown that no reliable neutrinoless double beta decays have been measured. In any case this would happen if neutrinos were Majorana neutrinos, which is not the standard model hypothesis.

Revised August 2013 by P. Vogel (Caltech) and A. Piepke (University of Alabama). Neutrinoless double-beta (0νββ) decay would signal violation of total lepton number conservation. The process can be mediated by an exchange of a light Majorana neutrino, or by an exchange of other particles. However, the existence of 0νββ decay requires Majorana neutrino mass, no matter what the actual mechanism is.

There are only limits.

Lepton number conservation is well tested in much cleaner interactions.

In any case in the diagram you give I do not see any annihilation, it would need an extra vertex. I see a W- decaying into a neutrino and an electron , and the Majorana neutrino (which is its own antiparticle) going into W+ ( reading W-the diagram line backwards) + electron. The probability would be very small because in the nucleus the Ws are very much off shell, and the propagator comes in twice.

$\endgroup$
4
  • $\begingroup$ Yes, the process is obviously BSM, however from a theoretical point it is very likely that neutrinos are Majorana particles. And the half life is at least >10^25y (from experiments). By the way, lepton number is marginally violated in the SM (not BSM) through chiral anomalies related to instanton tunneling. $\endgroup$
    – 0vbb
    Commented Mar 3, 2016 at 13:05
  • $\begingroup$ i am ignorant of the situation.. theoretically as @MichaelMoser says, it is possible to violate lepton number in the non perturbative regime in the SM, but has it not been observed experimentally yet/are such violations smaller than what can be set by experimental bounds? $\endgroup$
    – Bruce Lee
    Commented Mar 3, 2016 at 14:37
  • $\begingroup$ @Bruce I haven't updated my post at physics.stackexchange.com/questions/28279/… recently, but there are several major campaigns underway to text the Majorana neutrino hypothesis, and they are nearing the design target for nuclei days tested without a positive announcement yet. $\endgroup$ Commented Mar 3, 2016 at 15:10
  • $\begingroup$ @dmckee thanks for your reference as I learnt something new. However I was asking if the lepton number violation in the nonperturbative regime of the Standard Model was ever observed? Or are such violations smaller than the experimental bounds? the post you referred to was about the Majorana Neutrino hypothesis by double beta decay. $\endgroup$
    – Bruce Lee
    Commented Mar 3, 2016 at 15:20
1
$\begingroup$

Neutrinoless double beta "decay" is not actually a decay but a multi-body scattering ($2\to 4$) where two neutrons scatter into two protons and two electrons. Lepton number is clearly violated by two units. In the example you give, the underlying process where the violation takes place is in the 2-body scattering: $W^- W^- \to e^- e^-$. This could be mediated by a $t$-channel Majorana neutrino or something else, e.g. by a hypothetical doubly-charged $\phi^{--}$ scalar in the $s$-channel (or you can even have two BSM gauge bosons emitted by each neutron scatter into $e^- e^-$). The actual mechanism of how the violation takes place cannot be probed in the experiment, just lepton number violation.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.