"In the RGB color model, the light of two complementary colors, such as red and cyan, combined at full intensity, will make white light, since two complementary colors contain light with the full range of the spectrum." https://en.wikipedia.org/wiki/Complementary_colors#Colors_produced_by_light
Cyan light has wavelengths at around 495 nanometers, and red light about 700 nanometers. White light is light in which no color is seen. It looks like white, but actually consists of a combination of all visible colors.
The hue is determined by domination of the impression of one or two of the three types of cones. If the impressions are the same, we see white or gray, depending on the intensity.
Do I have to understand that because at 495nm (cyan) the S and M have a intersection point, by means that the S and M cones are impressed at the same level (at sensity 0.3) together with red (L) at the wavelength of 640nm also at sensity 0.3 (instead of 700nm). And this together creates white?
But with the two wavelengths 640 and 495nm can't be said that it contains light with the full range of the spectrum as is said in wikipedia. Fe if I have two lasers one with 495nm color and the other with 640nm and I mixe them will I see also white light? Or does it not work like that to create white light with complementary colors?