Charges loose their energy within the circuit if they move through a resistor(like a bulb). Now, if I make a circuit with just wires and no resistor, will the charge loose its energy?
One reason of loss of energy of the charge I can think of is that as the charge reaches the positive terminal, it it getting closer to the positive charge which is attracting it, and getting closer to the source of the electric field, and hence, it is loosing potential energy(Similar to the case of the gravity of earth, as we move closer to ground, we loose potential energy). And, this potential energy is converted to the kinetic energy of the charge.
Now, using all of the things I wrote above, we can ask the question that as the charge reaches the positive terminal, where is this Kinetic energy lost? If it isn't lost, then will the battery work properly? Because on reaching the positive terminal, charge already has energy, so what will the battery do?
Of course due to the very less resistance of the wire, the charge will loose some energy, but it will be extremely small. So, is this Kinetic energy lost? If not, what is the case with this circuit?