I thought I'd have an order of magnitude attempt at answering your edit.
First, there is nothing magical about its orbit in the galactic potential - dark matter particles (if that's what they are) should orbit just like any other point (baryonic) mass. But, the baryonic mass is predominantly in orbits confined to a disc, whereas dark matter is thought to be much more spherically symmetric. All these orbits will not be exact Keplerian ellipses, since the Galactic potential is not that of a point mass.
The typical velocities of dark matter will be similar to that of normal matter at the same galactocentric radius, but in pseudo-random directions. The net result is that from the point of view of a star at the radius of the Sun, the dark matter is like a wind blowing at $\sim 220$ km/s.
So now to the black hole problem. Black holes are the endpoints of massive stars. Empirically, they seem to cluster in mass at a little below $10 M_{\odot}$ (but let's just assume 10). The number of Galactic black holes is highly uncertain, dependent on the form of the stellar initial mass function (as a function of epoch and perhaps metallicity) and the uncertain physics of mass loss from massive stars (again, as a function of metallicity). However, $10^8$ is not unreasonable.
Massive stars are predominantly formed, live and die in the disc. Let's conservatively assume no "kick" from any supernova and that black holes orbit in the disc with a similar speed to the stars around them. Thus they will pass through a dark matter medium, at a speed of 220 km/s, with an estimated density at the Sun's position is about 0.3 GeV/cm$^3 = 5\times 10^{-28}$ kg/m$^3$ (e.g. Read 2014).
We can treat the gravitational interaction in terms of Bondi-Hoyle accretion. Thus
$$ \dot{M} = \pi R^2 \rho v,$$
where $\rho$ is the dark matter density, $v$ is the relative speed, and $R$ is the Bondi-Hoyle radius, which can be estimated by equating the escape speed at $R$ with $v$. i.e.
$$ R = \frac{2GM}{v^2}$$
and hence
$$ \dot{M} = 4\pi \frac{(GM)^2 \rho}{v^3}.$$
Putting in the numbers, I get $\dot{M} \simeq 1$ kg/s or $1.6\times 10^{-23} M_{\odot}$/yr. Thus $10^{8}$ such black holes, accreting for $10^{10}$ years will accrete a tiny fraction of a solar mass of dark matter in the lifetime of the Galaxy.
There are perhaps caveats. The dark matter density is a bit higher nearer the Galactic centre, but on the other hand the rotation curve is quite flat, so it can't make many orders of magnitude difference to the result. The velocity used will have a distribution, so accretion will be stronger for slower dark matter. On the other hand, kicks from supernovae will increase $v$.Thus,I think the effect you are talking about is demonstrably negligible.