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If we place a wire within a uniform exterior magnetic field ($B_x$) that's perpendicular to it's length, and allowed current to flow withing the that conductive medium, there is another magnetic field generated from that wire ($B_w$). There is a Lorentz force as well, however, due to the $B_w$ existing with $B_x$ would they add or subtract from the net strength of each field?

Diagram:

enter image description here

The orange lines is of the exterior magnetic field, wanted to illustrate it in the most important views(right & top).

As a result of the magnetic field, there is a Lorentz force, would $B$ in the formula be only $B_x$? Why wouldn't it be ($B_x$ - $B_s$) or ($B_x$ + $B_s$)? Likewise, if the wire was able to accelerate in the the magnetic field, the induced motional EMF's $B$ be the same?

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B should remain since Magnetic field is added in upper part and equally subtracted in lower part.

Hint: Wire does not experience its own magnetic force.

If you let wire to accelerate in $B$ freely , it won't give any magnetic field.. So, no current flow in wire. Hence EMF is induced in opposite direction.

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  • $\begingroup$ I've adjusted the diagram, also,the magnetic field is uniform. I don't understand how and why it would be added in the upper part and subtracted in the lower part equally? Shouldn't they be the same at all points? $\endgroup$ – Pupil Feb 7 '16 at 6:00
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    $\begingroup$ In upper part both magnetic field are towards right. So, they are added. In lower part they are opposite in direction, so are subtracted. $\endgroup$ – Anubhav Goel Feb 7 '16 at 7:11

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