This question is indeed lengthy, but please go through the question at least.

From the study of kinetic theory I know that for intuitive answers we can associate the states (liquid, solid,gas) with the motion of their constituent particles that is for example in a gas particles can move freely much more than particles in liquids which in turn can move more freely as compared to solids that is if I need to convert water to gas I need to give it energy to its particle and excite it so that it can break away from the forces of attraction and move much freely.

But then I studied about sublimation and examples of say dry ice which convert directly to gaseous $CO_2$ even at room temperatures.

But based on this Analogy of kinetic theory shouldn't there be state of energy of the particles (associated with their movements) between the solid / gaseous state which we should term as liquid state as how is it possible that particles of Dry Ice whose movement was restricted very much suddenly turn into gaseous state having very high velocities?

Shouldn't this transition happen continuously rather than suddenly as projected by the term sublimation as most of the particles of solids have arrested movements and only sort of vibrate but in gases it is completely different so why shouldn't we term a state between them as liquid ? As we do in many other processes ?

Edit: I understand that melting/boiling point also depends on pressure which gives rise to phenomenon such as regelation but I am trying to ask a much basic question that is if particles (in say dry ice as above) have restricted movement and can only vibrate about their position then how can this be suddenly converted to gas in which the particles have very high velocities and can disappear into the air within a fraction of air !! What happened in between why the discontinuity ? This is what is troubling me here as there must be a state between solid-gas in which particles have greater velocity then solids but less than gaseous particle. A state which we commonly call liquid so why not do it this time and say transition between states happened like this solid Dry ice( particles have very low velocities)→liquid Dry ice(particles can roam much freely)→gaseous dry ice(particles have gone crazy and are roaming here and there as they wish as very little force of attraction is there.)

But instead of this we use the term sublimation, which doesn't tell the whole story.So why do we use this term for some substances at some temperatures and for some we do not,if we know that the transition is always happening continuously?


3 Answers 3



Generally, all phase transitions require some input energy in order for the transition to occur. For instance, the transition from solid-to-liquid or vice versa requires what is called the enthalpy of fusion or latent heat of fusion. This is the amount of energy needed to change the total interal energy (i.e., enthalpy) of a substance in order to produce the phase transition. The amount of energy necessary to produce sublimation is, not too surprisingly, called the enthalpy of sublimation.

For example, imagine we had water ice at $-10^{\circ}$ C and we wanted to convert this to a gas. We would need to add energy, but it would occur in the following steps:

  1. add enough energy to change the temperature of the ice from $-10^{\circ}$ C to $0^{\circ}$ C;
  2. add enough energy to overcome the latent heat of fusion;
  3. add enough energy to change the temperature of the ice from $0^{\circ}$ C to just below $100^{\circ}$ C;
  4. add enough energy to overcome the latent heat of vaporization; and finally
  5. add more energy to increase the temperature of the steam (if one so desires, so long as the steam is contained).

The process would occur in these steps under STP if we added the energy continuously in at a slow rate (i.e., supply slighly more energy than is lost through radiation and/or conduction). It is possible to sublimate ice into a vapour but this generally occurs through ablation by UV light (and/or higher energy photons).

Why do some substances undergo sublimation while others do not?

The answer lies in thermodynamics, specifically the triple point of the substance. If this occurs at a large pressure compared to STP, then it is possible for a material to sublimate. For instance, if you look at the phase diagram image below you can see that the sublimation point for CO$_{2}$ occurs at a lower temperature and pressure than its triple point. Whereas, water has a triple point at a much lower pressure than standard atmospheric pressure, so sublimation is less likely to occur under normal conditions (and in the absence of high energy photons or particles that can induce ablation).

phase diagram for water and carbon dioxide

Thus, if you continously add energy to solid CO$_{2}$, its first transition will be to a gaseous form not a liquid form under STP. If you increased the pressure on the system and then added energy, so long as the pressure is high enough then you can produce a liquid CO$_{2}$. The substance's chemical properties determine its critical and triple points and these have been well documented for most substances.

as there must be a state between solid-gas in which particles have greater velocity then solids but less than gaseous particle...

No, there must not. If you add enough energy to induce a phase transition and it is easier for the substance to change into a gas than a liquid, it will go straight to the gaseous form, not though the liquid.

so why do we use this term for some substances at some temperatures and for some we do not...if we know that the transition is always happening continuously.?

A phase transition is, by definition and occurrence, a discontinuous change. The problem is, while you can change the temperature of a substance in a semi-continuous manner when it is far away from any phase transition lines, once at a phase transition line you can add energy but see no change in temperature until the substance undergoes the phase transition. Then, once in the new state, the substance can change temperature again (assuming the transition was not bounded by another phase transition line) in a semi-continuous manner by adding more energy.

You can try this at home with a standard cooking thermometer. Start with near-ice-cold water and then raise it to a boiling temperature. Make sure the thermometer is not touching the metal pot/pan in which the water lies. If your oven surface elements provide a roughly constant energy to the pan, then you should see a semi-continuous change in temperature up until just under $100^{\circ}$ C. If you keep the heat low enough, you can sit at this point, just below boiling, for a relatively long time. This is because the rate at which you add energy may be only just overcoming radiative and conductive heat losses to the surrounding room. If you crank up the heat, the time spent just below the $100^{\circ}$ C mark will be much shorter as your energy input can vastly exceed radiative and conductive losses.

Caveats and Notes

Note that phase transitions are defined within the context of thermodynamics, which is, by construction, a fluid model (i.e., meant for macroscopic parameter space) not a kinetic model. Note that kinetic models can describe macroscopic parameters as well, but they do so by finding the ensemble average in velocity space of the distribution function to treat a large number of particles as if they exhibit a bulk behavior similar to a fluid.

The differences between fluid and kinetic models can be subtle, but you can think of them in the following ways.

  1. We treat fluids as a continuous blob occupying a unit volume that can deform under stress but the initial fluid element, if incompressible, will occupy the same volume.
  2. For kinetic models, we assume a model distribution function that most closely describes the discrete particles in the system. In many cases, this function is continuous in the mathematical sense and the use of ensemble averages can yield bulk properties similar to those in thermodynamics (e.g., temperature). However, the interpretations are often different and the limitations and assumptions required in kinetic models are generally fewer than fluid models.

Continuous vs. Discontinuous
When I use the term discontinuous above, I am referring to a change that occurs on a smaller scale than the resolution of the specific observation. For instance, we assume that shock waves contain a discontuous jump in density, pressure, etc. in a region called the ramp. This region is generally assumed to be "infinitely" thin when looking at the asymptotic state of the fluid/kinetic gas on either side of the ramp. However, it is well known that the ramp has a finite thickness of the order of $\sim 1 \ \mu m$ in Earth's atmosphere at STP. For most fluid models, this spatial scale is so small we can approximate it as being infinitesimal and neglect it. This approximation greatly simplifies many of the equations we would use to try and model such phenomena, even though the transition from upstream to downstream is not truly discontinuous. We define the transition as being discontinuous because it is comparable to or smaller than the smallest relevant scale lengths considered for the problem at hand (i.e., in this case, the inter-particle mean free path).

In nature, there are few things that could be truly called discontinuous (I actually know of none, but some of the quantum whisperers on this site might know of some. Thus I am trying to be careful in this statement.). However, that some phenomena changes continuously on the smallest scales may not matter for the macroscopic dynamics where we assumed a discontinuous change. As in the shock wave example above, that the ramp region has a finite thickness does not render the conservation relations used to model most shocks (i.e., Rankine-Hugoniot relations) useless. The assumption that the ramp is discontinuous works because the transition is faster than the scales (i.e., fluid) considered in this specific problem. Thus, the definition of continuous vs. discontinuous depends upon the problem being addressed!

So in the purest sense, yes, a phase transition is close to (not exact because particles are discrete) a continuous transition if we could measure things "infinitely" fast and on an "infinitely" small scale.

Interesting Side Note: The use of a model distribution function generally inserts irreversibility into any model one would evolve dynamically from this point forward.


The phase diagram image was taken from Wikipedia, courtesy of Cmglee - Own work, CC BY-SA 3.0, https://commons.wikimedia.org/w/index.php?curid=29176053

  • $\begingroup$ Good explanation. To make it better, I would recommend including $CO_2$ phase diagram you linked to. Either screenshot the figure and save as a png file or use Inkscape to export a png from the svg file. $\endgroup$ Feb 9, 2016 at 18:36
  • $\begingroup$ @NauticalMile - I would but I am not sure about copyright issues with stealing an image directly from Wikipedia... $\endgroup$ Feb 9, 2016 at 19:17
  • 1
    $\begingroup$ According to this link you can see the diagram is under the creative commons license, meaning you can share the image anywhere you like, as long as you attribute the author. There is a very easy way to attribute the authors of Wikimedia images -> click on the download button in the bottom right hand corner of the above link and then click where it says "You need to attribute the author" copy and paste the html reference into the answer box, just below the image. Voila :) $\endgroup$ Feb 9, 2016 at 20:51
  • 2
    $\begingroup$ @NauticalMile - Done. $\endgroup$ Feb 10, 2016 at 23:56
  • $\begingroup$ @honeste can you please clarify the comments below (I know they are a bit long but still...)... $\endgroup$
    – Freelancer
    Feb 11, 2016 at 13:49

Whether one sees a solid or a liquid or a gas is determined by the correlation properties of the molecules in the substance. Solids (in crystals) have strong and long-range correlations, liquids have no long-range but strong short-range correlations, while gases have almost only weak intermolecular correlations.

In the part of the phase diagram below the triple point, crossing the coexistence line from solid to gas means that upon adding energy, single molecules separate from the surface in an only weakly uncorrelated way and therefore immediately behave like molecules of a gas.

On the other hand, in the part of the phase diagram above the triple point, crossing the coexistence line from solid to liquid means that upon adding energy, the surface breaks into many tiny (and not very well-defined) regions consisting of few highly correlated molecules and therefore immediately behave like molecules of a liquid, characterized by strong short-distance correlations.

For a very small piece of solid, the distinction between gas and liquid is not very pronounced, but for solids of the size relevant on human time scales, we are already very close to the (infinite volume) thermodynamic limit where these effects happen instantaneously. Thus the transition is almost instantaneously.

If you want to know what happens in more detail than what you get from bulk statistical mechanics you need to look at adsorption/desorption processes at a solid surface. See https://de.wikipedia.org/wiki/Adsorption - This is primarily used for the contact of different substances, but freezing and melting/sublimation work essentially in the same way as adsorption and desorption, respectively.


Phase changes depend not only on temperature but also pressure. Like any substance, if you get the right combo of pressure and temperature you can keep it at a solid, liquid or gas or if you're really good keep it at the triple point and get all three phases in equilibrium with each other. For C02, the liquid phase is very likely outside of most temperature pressure combos used in engineering applications and everyday life.

  • 2
    $\begingroup$ you should give a link for the phase diagrams en.wikipedia.org/wiki/Phase_%28matter%29 $\endgroup$
    – anna v
    Feb 5, 2016 at 19:15
  • 1
    $\begingroup$ @Freelancer , water can also sublimate. At freezing temperatures, and VERY low pressures, there are points on the water phase diagram that indicate that it will go directly from a solid to a vapor if you add heat to it. $\endgroup$ Feb 5, 2016 at 23:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.