Can this Temperature Scale be Considered an absolute temperature scale?

Me and My friend are having a discussion about Absolute Temperature Scales. I think Absolute Temperature Scales are those who have their zero on Absolute zero. So Can we define a new Scale (say "Namu"), which is defined as $\frac{1}{8}*K$ where K is the Kelvin Scale, and say that this scale is absolute? If Yes, Can we really make temperature scales of our own (even if it won't be much significant)? Or are there some bounds place upon the creation?

• Yes, that works. – mmesser314 Feb 4 '16 at 15:10
• @mmesser314.. was that an answer for both my questions? – prakhar londhe Feb 4 '16 at 15:17
• Please someone explain the downvote – prakhar londhe Feb 4 '16 at 16:06
• There are two aspects to a temperature scale: 1) where you put the zero, and 2) the unit ( size of your degree). For an absolute scale there is only one choice for 1, but you are free to choose 2 however you like. – Lewis Miller Feb 4 '16 at 16:07

• The Kelvin scale is linear in the sense that for an ideal gas the internal energy is proportional to the temperature. So each extra degree K adds the same increment of internal energy. If you want your Namu scale $T_N$ to preserve this linearity then it needs to be related to the Kelvin scale $T_K$ by $T_N = aT_K + b$ where $a$ and $b$ are constants. I'm guessing this is what you mean by your expression mK + c. If you're not fussed about the linearity then you could use a more general scale, but all your equations will get more complicated if you do. – John Rennie Feb 4 '16 at 16:37