I have a problem understanding these basics. What is the tension in the ground rod due to the forces exerted by the slanted rods?
Please feel free to correct me at any point.
Rods are idealized and are long, light and thin, welded together to form a static structure in the form of an equilateral triangle. On the left, the weight of the load $F$ compresses the two standing slanted rods, with compression in both of them equalling $F / (2 sin 30^\circ)$. They in turn pull apart the ground rod with tension that equals the horizontal component of $F_1$ -- or is it two times that amount -- so $F / (2 ctg 30^\circ)$ or is it $F / (ctg 30^\circ)$?
On the right, it's no different for the slanted rods, but the ground rod here is not in equilibrium because of the non-existing horizontal force of the right rod but because of friction. Yet the tension in this rod is the same as it is in the example on the left?
I can see my drawing isn't too helpful, yet I don't think it matters much how it's drawn; the rods are long, thin, light, and welded together. True, there should be any contact between the two standing rods and the ground (in the left case).
What's the tension then in the pink rod below. Is it the force exerted by each standing rod or is it twice that amount since each rod is pulling it apart?