# Tension in string of two pulleys suspending two masses [closed]

There is a system composed a rope connecting two identical masses, each of mass $m$, suspended by two fixed pulleys. The system is in a static equilibrium.

In between the pulleys, there is a tension gauge in the rope. It is my understanding that this tension gauge should read $mg$, as it is being pulled on both ends with a force of $mg$, exactly the same as if it were simply suspended from a fixed point holding a mass of $m$.

However, my professor says the tension gauge reads $\frac{mg}{2}$. What is correct, and why? ## closed as off-topic by stafusa, Kyle Kanos, glS, Jon Custer, JMacAug 27 '18 at 18:04

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – stafusa, Kyle Kanos, Jon Custer
If this question can be reworded to fit the rules in the help center, please edit the question.

The professor is wrong (for how you labeled the diagram). The answer is $mg$. But if he meant $m_{total} g / 2$ he was correct. That is $(m_1+m_2) g / 2$ is the correct answer.