So the equation Favg * d = Work or change in kinetic energy, is this true? If a car crashes into a tree by 1 meter with 10000 joules, is the impact force on the car 10000 Newtons? If a bullet penetrates .3048 meters with 500 Joules is 1640.41 Newtons exerted on the target it hits, and assumed the impulse is 1 second, should it accelerate and move an object, if it moves that object over a distance, will it do work? Is this correct?
closed as off-topic by Bill N, Gert, Kyle Kanos, user36790, ACuriousMind♦ Jan 30 '16 at 15:26
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The work energy theorem stares that the work done is equal to the change in kinetic energy. Work is force time distance moved in the direction of the force. To do work the force must move. Do not forget that you are finding the average force during the interaction. If you know the time over the interaction takes place then this will give you the average acceleration.