Superficial degree of divergence on Weinberg Reading volume 1 of Weinberg's QFT book, chapter 12, page 505 he says that if you consider a diagram with degree of divergence $D\geq{}0$, its contribution can written as a polynomial of order $D$ in external momenta. As an example he considers the $D=1$ integral
$$\int_0^{\infty}\frac{k\,dk}{k+q}=a+bq+q\ln{q}.$$
where $a$ and $b$ are divergent constants, and we see that we get a polynomial or order 1 in the external momenta $q$. He then says, and I quote

"Now, a polynomial term in external momenta is just what would be produced by adding suitable terms to the Lagrangian, if a graph with $E_f$ external lines of type $f$ (refering to field type) has degree of divergence $D\geq{}0$, then the ultraviolet divergent polynomial is the same as would be producedby adding various interactions $i$ with $n_{if}=E_f$ fields of type $f$ and $d_i\leq{}D$ derivatives."

Can anybody elaborate on this a bit? in particular, how and where does the polynomial arise with the added Lagrangian term?
 A: *

*Disclaimer: Renormalization is a huge subject with many facets, such as, e.g. overlapping divergences of subgraphs, regularization, renormalization group, etc. Here we will only elaborate on OP's quote from Ref. 1.

*Ref. 1 is considering a Feynman diagram ${\cal F}(q_1, \ldots, q_E)$ in momentum Fourier space, with external 4-momenta $(q_1, \ldots, q_E)$, and with internal 4-momenta $(p_1, \ldots, p_I)$, which are integrated over. The $p$-integrations are assumed to be UV divergent with positive superficial degree of divergence (SDOD) $D\geq 0$. Concerning SDOD, see e.g. my related Phys.SE answer here.

*Here $E=\sum_f E_f$ is the total number of external lines, and $E_f$ is the number of external lines of field type $f$.

*If we differentiate the Feynman diagram $D+1$ times wrt. the external 4-momenta, the integrand becomes UV finite. We conclude that the divergent part of the original Feynman diagram ${\cal F}(q_1, \ldots, q_E)$ is a polynomial in $(q_1, \ldots, q_E)$ of order $\leq D$. Note that the coefficients of the polynomial are possibly infinite!

*We next add new interaction terms to the Lagrangian density ${\cal L}$ corresponding to $E$-vertices with $E_f$ fields of field type $f$, and possibly a finite number of spacetime derivatives (which in momentum Fourier space becomes a momentum monomial). The new interaction terms are so-called counterterms.  

*Feynman instructs us to sum over all Feynman diagrams with $E_f$ external legs of field type $f$. In particular, we should also include diagrams consisting of a single $E$-vertex coming from the new interaction counterterms. By adjusting possibly infinite coupling constants in front of the new interaction counterterms, the full Feynman diagram can be made finite.
References:


*

*S. Weinberg, Quantum Theory of Fields, Vol. 1; Section 12.2, p. 506.

*M.E. Peskin & D.V. Schroeder, An Intro to QFT, 1995; Section 10.1, p. 319.
